PHP轉換時間格式

Question

在我的數據庫中有一個日期，如2013/11/12，它必須轉換爲12th November 2013。這裏有我的代碼：

$a=mysqli_connect("localhost","usern","pass","my_mk7vrlist"); 

//as you can see I'm getting the value of the date from a MySQL database 

$res= mysqli_query($a,"SELECT * FROM 0_vrs_europe ORDER BY `vrs` DESC, `date` ASC LIMIT 0 , 150"); 

while($row = mysqli_fetch_array($res)) 
    { 
    echo "<tr>"; 
    echo "<td>" . $row['status'] . "</td>"; 
    echo "<td>" . $row['date'] . "</td>"; 
    echo "</tr>"; 
    } 

mysqli_close($res); 
?> 

的$row['date']包含2013/11/12格式的日期和它必須12th November 2013因爲我已經說過轉換。我怎麼能這樣做？

我GOOGLE了功能date但我不明白如何在這裏使用它。

Answer 1

使用date()的第二個參數：

$formatted = date('jS F Y', strtotime($row['date'])); 

Answer 2

$date = date("jS F Y", strtotime($row['date']));