2016-12-19 52 views
0

我正在使用NSKeyedArchiver & NSKeyedUnarchiverCore-Data中存儲一些複雜數據,稍後在我的應用中檢索它。 這直到現在都完美運行,但在遷移之後,Swift 3.0似乎並不滿意我的代碼。NSKeyedArchiver&NSKeyedUnarchiver/Swift 3.0

我有這個在我的代碼早:

 var firstArray = [Int](), secondArray = [CGFloat]() 
     ....... 
     // stores some values in firstArray and also in secondArray. 
     ....... 

這裏是存儲數據的代碼看起來像:

 let masterArray = [firstArray, secondArray] as [Any] 
     let dataForApp:NSData = NSKeyedArchiver.archivedData(withRootObject: masterArray) as NSData 
     entityFieldsDico = ["dataForAppArray":dataForApp] 
     // Use entityFieldsDico to save dataForApp in Core-Data under the key "dataForAppArray". 

下面是代碼如何檢索數據看起來像:

if let archiveData = dbRecord.value(forKey: "dataForAppArray") { 
     let archiveArray = NSKeyedUnarchiver.unarchiveObject(with: archiveData as! Data) 
     firstArray = (archiveArray as! Array)[0] as [Int] 
     secondArray = (archiveArray as! Array)[1] as [CGFloat] 
    } 

問題出現在代碼檢索數據。它只是在構建時崩潰。

如果我註釋掉那些2線:

 //firstArray = (archiveArray as! Array)[0] as [Int] 
     //secondArray = (archiveArray as! Array)[1] as [CGFloat] 

該項目工程,除了不具備的事實firstArray &的數據是(明顯)。

如果我不評論他們,那麼我會發生崩潰,並有一個非常長的消息以類似於下面的內容結束。 (我補充一些...(點),以縮短信息。)

............. 
0 swift     0x000000010d71fa3d PrintStackTraceSignalHandler(void*) + 45 
1 swift     0x000000010d71f466 SignalHandler(int) + 470 
2 libsystem_platform.dylib 0x00007fffa0c5a52a _sigtramp + 26 
3 libsystem_platform.dylib 0x0000000000000003 _sigtramp + 1597659891 
4 swift     0x000000010b25b4e3 swift::constraints::ConstraintGraphScope::~ConstraintGraphScope() + 899 
5 swift     0x000000010b2f45f4 swift::constraints::ConstraintSystem::solveSimplified(llvm::SmallVectorImpl<swift::constraints::Solution>&, swift::FreeTypeVariableBinding) + 24868 
........... 
Objects-normal/arm64/UP_ViewController.dia -emit-dependencies-path /Users/me/Library/Developer/Xcode/DerivedData/TheApp-dszaazmmftlmwbicuwcwaplkjdfs/Build/Intermediates/TheApp.build/Debug-iphoneos/TheApp.build/Objects-normal/arm64/UP_ViewController.d -emit-reference-dependencies-path /Users/me/Library/Developer/Xcode/DerivedData/TheApp-dszaazmmftlmwbicuwcwaplkjdfs/Build/Intermediates/TheApp.build/Debug-iphoneos/TheApp.build/Objects-normal/arm64/UP_ViewController.swiftdeps -o /Users/me/Library/Developer/Xcode/DerivedData/TheApp-dszaazmmftlmwbicuwcwaplkjdfs/Build/Intermediates/TheApp.build/Debug-iphoneos/TheApp.build/Objects-normal/arm64/UP_ViewController.o -embed-bitcode-marker 
1. While type-checking 'computeFunction' at /Users/me/Documents/iOS/TheApp/TheApp/UP_ViewController.swift:184:5 
2. While type-checking expression at [/Users/me/Documents/iOS/TheApp/TheApp/UP_ViewController.swift:235:17 - line:235:66] RangeText="firstArray = (archiveArray as! Array)[0] as [Int]" 

我的人經歷了這樣的問題,請讓我知道你是怎麼解決它。

+0

結帳我的回答 –

回答

1

您需要將您的archiveArray轉換爲Array<Array<Any>>,然後才能獲得包含Any類型值的數組數組。

您的解決方案是

if let archiveData = dbRecord.value(forKey: "dataForAppArray") { 
      if let archiveArray = NSKeyedUnarchiver.unarchiveObject(with: archiveData as! Data) as? Array<Array<Any>> { 
       firstArray = archiveArray[0] as! [Int] 
       secondArray = archiveArray[1] as! [CGFloat] 
      } 

} 

讓我們看一個例子的麪糊瞭解

var firstArray = [Int](), secondArray = [CGFloat]() 
firstArray.append(1) 
firstArray.append(1) 
firstArray.append(1) 

secondArray.append(1.1) 
secondArray.append(1.2) 
secondArray.append(1.3) 

print(firstArray) //[1, 1, 1] 
print(secondArray) //[1.1, 1.2, 1.3] 

let masterArray = [firstArray, secondArray] as [Any] //[[1, 1, 1], [1.1, 1.2, 1.3]] 
let dataForApp:NSData = NSKeyedArchiver.archivedData(withRootObject: masterArray) as NSData 

現在unarchiveObject其返回Any然後打印輸出,從而能夠區分兩個輸出。

let archiveArray1 = NSKeyedUnarchiver.unarchiveObject(with: dataForApp as Data) 
print(archiveArray1!) 

輸出將是

(
     (
     1, 
     1, 
     1 
    ), 
     (
     "1.1", 
     "1.2", 
     "1.3" 
    ) 
) 

現在投陣列Array<Array<Any>>

if let archiveArray = NSKeyedUnarchiver.unarchiveObject(with: dataForApp as Data) as? Array<Array<Any>> { 
      print(archiveArray) 
} 

輸出將被

[[1, 1, 1], [1.1, 1.2, 1.3]] 

希望你能理解我的觀點。

+0

嗨,你的解決方案看起來不錯。我需要努力才能使其發揮作用。 我的第一次審判失敗。我會隨時向你通報。 – Michel

+0

好的謝謝米歇爾 –

+0

你在第一次試驗時面臨什麼樣的問題? –