從Postgres中的JSON數組中選擇

Question

Postgres中有這種方法嗎？

SELECT * FROM magic_json_function('[{"col1": 1, "col2": "A"}, {"col1": 2, "col2": "B"}]') 

col1 | col2 
------+------ 
1 | A 
2 | B 
(2 rows) 

編輯：，而無需創建一個表。

Answer 1

這是我最後只是：

SELECT value->>'col1' AS col1, value->>'col2' AS col2 
FROM json_array_elements('[{"col1": 1, "col2": "A"}, {"col1": 2, "col2": "B"}]') 

col1 | col2 
------+------ 
1 | A 
2 | B 
(2 rows) 

Answer 2

當然，功能json_populate_recordset。假設有通過

CREATE TABLE test(
    col1 int, 
    col2 text 
); 

定義的表test你可以簡單：

SELECT * FROM json_populate_recordset(NULL::test,'[{"col1": 1, "col2": "A"}, {"col1": 2, "col2": "B"}]')