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我需要一些幫助。我目前正在開發我公司的網站，並且一切都很順利，直到我測試了管理員帳戶（我使用的）的更改密碼功能。我已經爲擁有自己更改密碼功能的員工設置了一個單獨的帳戶。我的問題是每當我更改密碼時，它也會將職員帳戶的密碼更改爲同一個密碼。更改管理員帳戶的密碼也會影響員工帳戶
下面是密碼的變化PHP代碼：
<?php
session_cache_limiter("private");
$cache_limiter = session_cache_limiter();
session_cache_expire(180);
$cache_expire=session_cache_expire();
session_start();
if(isset($_SESSION['acc_uname'],$_SESSION['acc_pword']))
{
$acc_uname=$_SESSION['acc_uname'];
$acc_pword=$_SESSION['acc_pword'];
require_once('/home/a9440778/public_html/registration/connect.php');
function escape_data($data)
{
global $dbc;
if(ini_get('magic_qoutes_gpc'))
{
$data=stripslashes($data);
}
return mysql_real_escape_string($data,$dbc);
}
error_reporting(E_ALL & ~E_NOTICE);
echo"<!DOCTYPE html PUBLIC '-//W3C//DTD XHTML 1.0 Transitional//EN' 'http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd'>
<html xmlns='http://www.w3.org/1999/xhtml'>
<head>
<meta http-equiv='Content-Type' content='text/html; charset=iso-8859-1' />
<title>
Natuna Scean Manpower Corporation
</title></head>";
if(empty($_POST['acc_pword1']))
{
$acc_pword1=false;
echo"<b>Old Password</b> Contains null value<br>";
$retry=1;
}
else if($_POST['acc_pword1_err']=='1')
{
$acc_pword1=false;
echo"<b>Old Password</b> Contains invalid value<br>";
$retry=1;
}
else
{
$acc_pword1=md5(escape_data($_POST['acc_pword1']));
}
if(empty($_POST['acc_pword2']))
{
$acc_pword2=false;
echo"<b>New Password</b> Contains null value<br>";
$retry=1;
}
else if($_POST['acc_pword2_err']=='1')
{
$acc_pword2=false;
echo"<b>New Password</b> Contains invalid value<br>";
$retry=1;
}
else
{
$acc_pword2=md5(escape_data($_POST['acc_pword2']));
}
if(empty($_POST['acc_pword3']))
{
$acc_pword3=false;
echo"<b>Retype Password</b> Contains null value<br>";
$retry=1;
}
else if($_POST['acc_pword3_err']=='1')
{
$acc_pword3=false;
echo"<b>Retype Password</b> Contains invalid value<br>";
$retry=1;
}
else
{
$acc_pword3=md5(escape_data($_POST['acc_pword3']));
}
if($acc_pword3!=$acc_pword2)
{
$acc_pword3=false;
$acc_pword2=false;
echo"<b>New Passwords</b> do not match each other<br>";
$retry=1;
}
if($acc_pword1!=$acc_pword)
{
$acc_pword1=false;
echo"<b>Old Password</b> does not match<br>";
$retry=1;
}
if($retry=='1')
{
echo"<br><br><a href='javascript:history.go(-1)' target='middle'>retry encoding</a>";
}
else
{
echo"<script>
alert('Password Update Successful!');
window.location='http://natunascean.site88.net/admin/adminhome.php';
</script>";
/* echo"
<br><b>You had successfully updated your account</b><br><br>
<a href='' onclick='window.adminhome.php.reload(true)'>Done</a>"; */
$query=mysql_query("update account set acc_pword='$acc_pword2' where acc_pword='$acc_pword';")or die("JBSOFTWARES 1".mysql_error());
$_SESSION['acc_uname']="$acc_uname";
$_SESSION['acc_pword']="$acc_pword2";
$_SESSION['acc_type']="$acc_type";
}
}
else
{
echo"<center><br><br><img src='ops.png'></center>";
}
?>
我剛纔編輯的「window.location的」和零件的onClick其中adminhome.php爲管理員和crewhome.php爲職工
你假定每個人都有一個獨特的密碼？ :) – 2014-11-25 02:10:44
所以你現在*開發一些使用不推薦的'mysql_'函數？個人不想聘請你作爲開發人員。 – 2014-11-25 02:15:32