我有一張桌子,我可以添加圖像onclick。該表是從表單動態創建的。我試圖將表保存到本地存儲,但我收到了循環引用問題。我已閱讀Example of a circular reference in Javascript?,但我是一個完全新手,並努力去理解。你能指出一下嗎?此代碼中的循環引用在哪裏?
function makeChart() {
var table = document.createElement('table'),
taskName = document.getElementById('taskname').value,
header = document.createElement('th'),
numDays = document.getElementById('days').value, //columns
howOften = document.getElementById('times').value, //rows
row,
r,
col,
c;
var cel = null;
var myImages = new Array();
myImages[0] = "http://www.olsug.org/wiki/images/9/95/Tux-small.png";
myImages[1] = "http://a2.twimg.com/profile_images/1139237954/just-logo_normal.png";
var my_div = document.createElement("div");
my_div.id = "showPics";
document.body.appendChild(my_div);
var newList = document.createElement("ul");
my_div.appendChild(newList);
if (taskName == '' || numDays == '') {
alert('Please enter task name and number of days');
}
if (howOften == '') {
howOften = 1;
}
if (taskName != '' && numDays != '') {
for (var i = 0; i < myImages.length; i++) {
var allImages = new Image();
allImages.src = myImages[i];
allImages.onclick = function (e) {
if (sel !== null) {
sel.src = e.target.src;
my_div.style.display = 'none';
sel.onclick = null;
sel = null;
}
};
var li = document.createElement('ul');
li.appendChild(allImages);
newList.appendChild(li);
}
my_div.style.display = 'none';
header.innerHTML = taskName;
table.appendChild(header);
function addImage(col) {
var img = new Image();
img.src = "http://cdn.sstatic.net/stackoverflow/img/tag-adobe.png";
col.appendChild(img);
img.onclick = function() {
my_div.style.display = 'block';
sel = img;
};
}
for (r = 0; r < howOften; r++) {
row = table.insertRow(-1);
for (c = 0; c < numDays; c++) {
col = row.insertCell(-1);
addImage(col);
}
}
document.getElementById('holdTable').appendChild(table);
document.getElementById('createChart').onclick = null;
console.log(table);
localStorage.setItem(name, JSON.stringify(table));
console.log(JSON.parse(localStorage.getItem(table)));
}
}
所有DOM元素都包含循環引用(例如通過'parentNode.childNodes ...'。將它們序列化爲HTML,而不是嘗試JSON字符串化。 – Bergi