這裏是我的代碼顯示動態信息PHP的
<?php
session_start();
include 'header.php';
$getUserInfo = mysql_query("SELECT * FROM Campaigns WHERE cid = '$cid'");
$userinfo = mysql_fetch_assoc($getUserInfo);
$cid = $getUserInfo['cid']; //ID
$CName = $getUserInfo['CName']; //Name
$CDesc = $getUserInfo['CDesc']; //Description
$CAmt = $getUserInfo['CAmt']; //Rate
$CReqs = $getUserInfo['CReqs']; //Requirements
?>
<html>
<body>
<h3><?php echo $cid;?>, <?php echo $CName;?></h3>
<p><?php echo $CDesc;?>
</body>
</html>
而且在PHP數據庫中的每個新項目我希望它可以動態顯示。
但由於某種原因沒有顯示信息。難道是因爲我使用getUserInfo
它不應該是'$ CID = $用戶信息[ 'CID'];'? – TheNytangel