我想從app_A打開一個iOS app_B,然後想要將app_B的數據放回到app_A中,在下面嘗試打開whatsapp,但沒有奏效。請幫助如何在iOS中實現這一點,在此先感謝。如何在Swift中點擊按鈕打開Whatsapp或其他iOS應用程序?
@IBAction func clickMe(_ sender: UIButton) {
let url = "https://api.whatsapp.com/send?00919599****** "
let whatUpUrl = NSURL(string: url)
if UIApplication.shared.canOpenURL(whatUpUrl! as URL){
UIApplication.shared.openURL(whatUpUrl! as URL)
} else {
//redirect to safari because the user doesn't have Whatsapp installed
UIApplication.shared.openURL(NSURL(string: "http://whatsapp.com/")! as URL)
}
}
@Sudhir&Ankit,謝謝,夥計們,有怎麼了打開的,但我也需要從第二個應用程序回撥我的第一個應用程序,你可以請建議 – equanimousFly
請你詳細說明一下嗎? –
@ Ankit:我想要app_B的callBack響應數據不需要它是wats up。例如當我從app_A打開app_B時,app_B執行一些任務,然後將響應返回給app_A。 – equanimousFly