Sequelize PG：選擇加入，訂單，限制

我使用Sequelize 3.30.0與Postgres。這是我要執行的查詢：Sequelize PG：選擇加入，訂單，限制

SELECT works.title, artists.name, artists.relevance 
FROM works 
JOIN artist_works ON works.work_id = artist_works.work_id 
JOIN artists ON artists.artist_id = artist_works.artist_id 
WHERE artists.label LIKE '%mozart%' 
ORDER BY artists.relevance DESC 
LIMIT 50

這是非常簡單和工程就像一個魅力，如果我直接做它的分貝。但是，試圖對Sequelize執行相同的操作似乎無效（無結果）。這是findAll選擇什麼樣子：

Work.findAll({ 
    attributes : ['title'], 
    include : [{ 
     attributes : [ 'name' ], 
     model : Artist, 
     where : { label : { $like : '%mozart%' } }, 
    }], 
    limit : 50 
})

的Sequelize生成的查詢是很令人費解：

SELECT "works".*, "artists"."artist_id" AS "artists.artistId", "artists"."name" AS "artists.name", "artists.artist_works"."artist_work_id" AS "artists.artist_works.artistWorkId", "artists.artist_works"."artist_id" AS "artists.artist_works.artistId", "artists.artist_works"."work_id" AS "artists.artist_works.workId", "artists.artist_works"."type" AS "artists.artist_works.type", "artists.artist_works"."artist_id" AS "artists.artist_works.artist_id", "artists.artist_works"."work_id" AS "artists.artist_works.work_id" 
FROM (
    SELECT "works"."work_id" AS "workId", "works"."title" 
    FROM "works" AS "works" 
    WHERE ( 
     SELECT "artist_works"."artist_work_id" 
     FROM "artist_works" AS "artist_works" 
     INNER JOIN "artists" AS "artist" ON "artist_works"."artist_id" = "artist"."artist_id" 
     WHERE ("works"."work_id" = "artist_works"."work_id") LIMIT 1 
    ) IS NOT NULL 
    LIMIT 50) AS "works" 
INNER JOIN (
    "artist_works" AS "artists.artist_works" 
     INNER JOIN "artists" AS "artists" ON "artists"."artist_id" = "artists.artist_works"."artist_id" 
    ) ON "works"."workId" = "artists.artist_works"."work_id" AND "artists"."label" LIKE '%-mozart-%';

請注意，如果沒有限制設置的查詢工作。此外，當我嘗試還要添加order選項時，查詢會凍結。想法？

來源

2017-02-15 Stefano Bider

存在相關問題Sequelize with NodeJS can't join tables with limit，並且解決方案似乎將subQuery: false添加到options對象的findAll方法中。它可以防止創建你所涉及的子查詢。

我創建了相同的關聯並添加了subQuery: false並且子查詢沒有生成，以及LIMIT和ORDER似乎工作。但是，如果您確實想使用subQuery選項，因此我建議您從node_modules/sequelize/lib/dialects/abstract/query-generator.js開始查看selectQuery的源代碼，因爲它未在文檔中提及，所以我不保證它可以正常工作

來源

2017-02-15 17:41:29 piotrbienias

subquery：false'解決方案該問題的確如此。謝謝！ –

Sequelize PG：選擇加入，訂單，限制

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