我有這樣的MySQL表,我有四列:LOCATION_ID,LOCATION_NAME,地址,城市映射三列到PHP數組
我需要做兩個下拉菜單,其中第一個下拉是城市名稱。所以,如果有10個同名的城市,下拉應該只有1個城市。選擇該城市後,相應的位置名稱應該到達下一個下拉列表 - 位置名稱。選擇位置名稱下拉菜單後,將顯示相應的地址。
我的一個邏輯是: 從數據庫中選擇所有不同的城市。用另一個查詢,選擇所有信息。
查詢: SELECT distinct(city) from locations;
這會給我的所有不同的城市名稱。
SELECT * from locations;
所有需要的數據
做一個數組,其中關鍵是城市名,並作爲陣列位置的詳細信息。像這樣的東西
Array
(
[0] => stdClass Object
(
[location_id] => 27
[location_name] => ANSND
[address] => some street 1
[city] => NYC
)
[1] => stdClass Object
(
[location_id] => 809
[location_name] => ANBC
[address] => some street 1
[city] => NYC
)
[2] => stdClass Object
(
[location_id] => 810
[location_name] => dasddsdss
[address] => some street 1
[city] => Calif
)
[3] => stdClass Object
(
[location_id] => 811
[location_name] => testing 6 feb
[address] => some street 1
[city] => Calif
)
)
我該怎麼在PHP中做到這一點?
Array
(
[NYC] => Array
(
[0] => stdClass Object
(
[location_id] => 27
[location_name] => ANSND
[city] => NYC
[address] => some street 1
)
[1] => stdClass Object
(
[location_id] => 809
[location_name] => ANBC
[city] => NYC
[address] => fsff
)
)
[Calif] => Array
(
[0] => stdClass Object
(
[location_id] => 810
[location_name] => dasddsdss
[city] => Calif
[address] => some street 1
)
[1] => stdClass Object
(
[location_id] => 811
[location_name] => testing 6 feb
[city] => Calif
[address] => some street 1
)
)
)
什麼是您的查詢?你有什麼問題請詳細解釋。 – Prakash
@Prakash編輯問題 – nirvair
您可以顯示錶格'位置'的10個數據嗎? – Prakash