如何用PHP使用MySQL在HTML按鈕

Question

PHP

$con=mysqli_connect("localhost","root","","mmogezgini"); 
$menuler = mysqli_query($con,"SELECT * FROM menuler"); 
while($menu = mysqli_fetch_array($menuler)) 
{ 
    echo "<button class=\"ust_link\" 
     onClick=\"window.location.href='Menu_Url.php'\">Menu_Name</button>"; 
} 
mysqli_close($con); 

MySQL的代碼已經準備就緒，MySQL連接是成功的，我只是不知道如何放置menu['name']和menu['url']代替Menu_Name和Menu_Url

Answer 1

試試這個代碼：一次

<?php 
while($menu = mysqli_fetch_array($menuler)) { 
    $name = $menu["Name'"]; 
    $url = $menu["url"]; 
?> 
    <button class="ust_link" onclick="window.location.href='<?php echo $url; ?>'"><?php echo $name; ?></button> 
<?php 
} 
?> 

這會是難以呼應了所有的HTML，因爲你」重新使用

onclick="location.href=''" 

它結合了單引號和雙引號

Answer 2

您有兩種可能性：

echo "<button class=\"ust_link\" onClick=\"window.location.href='". $menu['url'].".php'\">". $menu['name'] ."</button>"; 

或者：

echo "<button class=\"ust_link\" onClick=\"window.location.href='{$menu['url']}'\">{$menu['name']}</button>"; 

見PHP: echo - Manual

Answer 3

像這樣：

$con=mysqli_connect("localhost","root","","mmogezgini"); 
    $menuler = mysqli_query($con,"SELECT * FROM menuler"); 
    while($menu = mysqli_fetch_array($menuler)) 
     { 
     echo "<button class=\"ust_link\" onClick=\"window.location.href='".$menu['url'].".php'\">".menu['php']."</button>"; 
     } 
    mysqli_close($con); 

Answer 4

試試這個：

$con=mysqli_connect("localhost","root","","mmogezgini"); 
    $menuler = mysqli_query($con,"SELECT * FROM menuler"); 
    while($menu = mysqli_fetch_array($menuler)) 
    { 
     echo "<button class=\"ust_link\"onClick=\"window.location.href='".$menu['url'].".php'\">". $menu['name'] ."</button>"; 
    } 
    mysqli_close($con);