如何獲得一些PHP多維數組？

Question

如何一次調用所有標籤？

我curently做這樣的事情：

$artist['tags']['0']['name']; 
$artist['tags']['1']['name']; 
// and so on for all 5 (0-4) 


[tags] => Array 
     (
      [0] => Array 
       (
        [name] => hip-hop 
        [url] => http://www.last.fm/tag/hip-hop 
       ) 

      [1] => Array 
       (
        [name] => romanian 
        [url] => http://www.last.fm/tag/romanian 
       ) 

      [2] => Array 
       (
        [name] => romanian hip-hop 
        [url] => http://www.last.fm/tag/romanian%20hip-hop 
       ) 

      [3] => Array 
       (
        [name] => rap 
        [url] => http://www.last.fm/tag/rap 
       ) 

      [4] => Array 
       (
        [name] => hip hop 
        [url] => http://www.last.fm/tag/hip%20hop 
       ) 

     ) 

Answer 1

可以使用foreach通過循環遍歷所有的一個藝術家的標籤：

$tags = array(); 
foreach ($artist['tags'] as $tag) 
{ 
    $tags[] = $tag['name']; 
} 
echo implode(', ', $tags); 

Answer 2

使用foreach並在它們之間迭代。

好像你要使用這樣的：

foreach($artist['tags'] as $key => $value) 
    echo $value['name'] . ', '; 

Answer 3

foreach ($artist['tags'] as $tag) { 
    echo $tag['name']; 
} 

我覺得這是你問什麼...

Answer 4

foreach($artist['tags'] as $key => $value) 
echo $value['name'] . ' '; 

這將通過陣列循環，並將寫入標籤到響應