將兩個輸入轉換爲一個數組，輸入db codeigniter

Question

我正在忙着創建一個網頁，將圖紙發送到客戶端並創建發送給客戶端的收據。我遇到麻煩的部分是選擇要添加到收據中的圖紙並更改修訂。

圖紙信息分爲兩個表格。第一個包含圖紙編號，標題，等等，第二個只包含修訂歷史。這些表格由圖紙ID鏈接。

要發出圖紙，用戶必須勾選複選框並更改要發佈的圖紙的修訂版。

我想輸入到數據庫中，但我不知道如何創建數組。目前我的控制器需要獲取所有的下拉輸入，並只有勾選的複選框。我只想要與所選複選框關聯的下拉輸入由數據庫更新。

這是我的看法。

<h1>Issue drawing</h1> 
<br> 

<div id="body"> 
<div class="row"> 
     <div class="form-group-sm"><lable class="col-sm-2 control-label">Project number:</lable> 
    <?php 
     $js = 'onchange="this.form.submit()" class="form-control" id="focusInput"'; 
     echo form_open('dwg_issue/issue_dwg'); 
     echo "<div class=\"col-xs-2\">" . form_dropdown('project_no',$proj_num, $this->input->post('project_no'), $js)."</div>"; 
     echo form_error('project_no', '<div class="col-xs-4"><div class="alert alert-danger fade in"><a href="#" class="close" data-dismiss="alert" aria-label="close">&times;</a>','</div></div>'); 
    ?> 
     </div> 
     </div> 

     <?php 
      echo "<noscript>".form_submit('submit','Submit')."</noscript>"; 
      echo form_close(); 
     ?> 
    <form action="<?php echo base_url() . 'index.php/dwg_issue/issue'; ?>" method="post" accept-charset="utf-8" id="issue"> 

     <table title="Client information" class="table table-hover"> 
      <caption><b>List of drawings</b></caption> 
     <thead> 
      <tr><th>Project number</th><th>Drawing number</th><th>Client drawing number</th> 
       <th>Title</th><th>Drawn by</th><th>Revision</th><th>Drawn Date</th><th>Select</th> 
     </thead>  
     <tbody> &nbsp; 
     <?php 

//   var_dump($client_info); 
      if(!empty($result)) 
      { 
       foreach($result as $row) 
       { 
        echo "<tr>"; 
        echo "<td>" . $row->project_no . "</td>"; 
        echo "<td>" . $row->sws_dwg_no . "</td>"; 
        echo "<td>" . $row->client_dwg_no . "</td>"; 
        echo "<td>" . $row->dwg_title . "</td>"; 
        echo "<td>" . $row->dwg_by . "</td>"; 
        $rev = array('0' => $row->dwg_rev); 
        $rev_change = array(
         'B' => 'B', 
         'C' => 'C', 
         'D' => 'D', 
         'E' => 'E'     
         ); 
        $dropdown = array_merge($rev,$rev_change); 

        echo "<td>" . form_dropdown('dwg_rev['.$row->dwg_id.']',$dropdown) . "</td>"; 
        echo "<td>" . date('Y/m/d', strtotime($row->dwg_date)) . "</td>"; 
        echo "<td>" . form_checkbox('select['.$row->dwg_id.']',$row->dwg_id) . "</td>"; 
        echo "</tr>"; 
       } 
      } 

     ?> 
     </tbody> 
     </table> 

     <div class="row"> 
     <div class="col-xs-12 col-md-10">Please select client distribution here with other options</div> 
     <?php 
     echo "<div class=\"col-xs-6 col-md-2\"><button class=\"btn btn-md btn-primary btn-block\" type=\"submit\" form=\"issue\">Issue drawings</button></div>"; 
     ?> 
     </div> 
     <br> 


     <?php 
     echo form_close(); 
     ?> 

</div> 

我控制器

public function issue_dwg() 
{ 
    $data['proj_num'] = $this->model_proj->proj_num_all(); 
    if ($this->input->post('project_no') != '0') 
    { 
     $data['result'] = $this->model_issue->list_dwg($this->input->post('project_no')); 
    } 

    $data['main_content'] = 'issue_view'; 
    $this->load->view('includes/template.php', $data); 


} 

//This function takes the selected drawings and create and issue slip 
public function issue() 
{ 
    $rows = array(); 

    $num_results = count($this->input->post('select')); 
    for($i = 0; $i < $num_results; $i++) 
    { 
     $rows[$i]['select'] = $_POST['select'][$i]; 
     $rows[$i]['dwg_rev'] = $_POST['dwg_rev'][$i]; 
    } 



} 

的issue_dwg（）函數獲得填充與圖號的下拉並填充用分貝的結果圖。

issue（）函數需要處理髮布的信息並將其轉換爲數組以傳遞給數據庫。

（我想添加視圖頁面的圖像，但我沒有足夠的信譽做）

Answer 1

當你解析你的表格，你需要建立你的輸入，因此，當您提交形式，你結束了關聯數組：

目前您有以下：

//... 
echo form_dropdown('dwg_rev['.$row->dwg_id.']',$dropdown); 
echo form_checkbox('select['.$row->dwg_id.']',$row->dwg_id); 
//... 

提交時，它會發出以下後陣列：

"select" (array)[ 
    0 => "some select value", 
    1 => "some select value" 
], 
"dwg_rev" (array)[ 
    0 => "some dwg_rev value", 
    1 => "some dwg_rev value" 
] 

---

SOLUTION：

結構的形式是這樣的：

"result"[ 
    0 => [ 
      "select" => "some select value", 
     "dwg_rev" => "some dwg_rev value" 
    ] 
    1 => [ 
      "select" => "some select value", 
     "dwg_rev" => "some dwg_rev value" 
    ] 
] 

現在你可以用迭代：

//... 
echo form_dropdown('result['.$row->dwg_id.'][dwg_rev]',$dropdown); 
echo form_checkbox('result['.$row->dwg_id.'][select]',$row->dwg_id); 
//... 

這種方式，你會用一個數組作爲這樣結束了輕鬆地在您的控制器中使用foreach。