如何使用java web.xml打開URL時打開子目錄的HTML頁面

Question

我有一個場景，當用戶打開http://MYWEBSITE.com/abc/時，用戶被定向到位於abc子目錄中的xyz.html頁面。我正在使用Java進行Web開發。我怎麼能在web.xml中做到這一點？

P.S.網址是http://MYWEBSITE.com/abc/不http://MYWEBSITE.com/abc

Answer 1

，你可以在web.xml定義一個servlet過濾器這樣

<filter> 
    <filter-name>incompleteUrlFilter</filter-name> 
    <filter-class>com.mywebsite.IncompleteUrlFilter</filter-class> 
</filter> 

<filter-mapping> 
    <filter-name>incompleteUrlFilter</filter-name> 
    <url-pattern>/abc/*</url-pattern> 
</filter-mapping> 

和過濾器類是這樣的

package com.mywebsite; 

public class IncompleteUrlFilter implements Filter { 

    public void doFilter(ServletRequest req, ServletResponse resp, FilterChain chain) throws IOException, ServletException { 
     if(((HttpServletRequest)req).getPathInfo() == null){ // nothing after /abc/ ! 
      req.getRequestDispatcher("/abc/xyz.html").forward(req, resp); // forward to xyz.html 
     } else { 
      chain.doFilter(req, resp); // else continue as usual 
     } 
    } 

}