我做了我的形式表模式 這樣的:驗證形式與JavaScript
<form name="register" method="post" action="#" onSubmit="return validasi()">
<table width="507" border="0">
<h1 class="title"><a href="#">Form Perubahan Password</a></h1>
<tr>
<td width="190" ><span id="usernameerror" class="style20">Masukkan Username </span></td>
<td width="319"><input name="username" type="text"></td>
</tr>
<tr>
<td><span id="passworderror" class="style20">Masukkan Password Lama</span></td>
<td><input name="pass" type="password"></td>
</tr>
<tr>
<td><span id="password1error" class="style20">Masukkan Password Baru</span></td>
<td><input name="pass1" type="password"></td>
</tr>
<tr>
<td><span id="password2error" class="style20">Ulangi Masukkan Password Baru</span></td>
<td><input name="pass2" type="password"></td>
</tr>
<tr>
<td> </td>
<td><input type="submit" name="Submit" value="Submit">
<input type="reset" name="reset" value="Reset"></td>
</tr>
</table>
</form>
,並與JavaScript本我的驗證代碼。檢查出來..
<script language="javascript">
function checkName(register)
{
var eobj = document.getElementById('usernameerror');
var susername = register.username.value;
var oRE = /^[a-z0-9]+[_.-]?[a-z0-9]+$/i;
var error = false;
eobj.innerHTML = '';
if (susername == '') {
error = 'Error: Username tidak boleh kosong';
register.username.focus();
}
else if (!oRE.test(susername))
{
error="Salah format";
}
if (error)
{
register.username.focus();
eobj.innerHTML = error;
return false;
}
return true;
}
function validatePwd(register) /* old password verification */
{
var eobj = document.getElementById('passworderror');
var invalid = ' ';
var pw = register.pass.value;
var error = false;
eobj.innerHTML = '';
if (pw.length < 1)
{
error = 'Masukkan password anda';
}
else if (pw.indexOf(invalid) > -1)
{
error = 'Anda harus mengisi password';
}
if (error)
{
register.pass.focus();
eobj.innerHTML = error;
return false
}
return true;
}
function validatePwd1(register) /* password & retype-password verification */
{
var eobj1 = document.getElementById('password1error');
var eobj2 = document.getElementById('password2error');
var invalid = ' ';
var pw1 = register.pass1.value;
var pw2 = register.pass2.value;
var error = false;
eobj1.innerHTML = '';
eobj2.innerHTML = '';
if (pw1.length < 1)
{
error = 'Masukkan password anda';
}
else if (pw1.indexOf(invalid) > -1)
{
error = 'Anda harus mengisi password';
}
if (error)
{
register.pass1.focus();
eobj1.innerHTML = error;
return false
}
if (pw1 != pw2)
{
eobj2.innerHTML = ' password tidak sama, coba masukkan kembali password anda';
return false;
}
return true;
}
function validasi()
{
var form = document.forms['register'];
var ary = [checkName, validatePwd, validatePwd1];
var rtn = true;
var z0 = 0;
for (var z0 = 0; z0 < ary.length; z0++)
{
if (!ary[z0](form))
{
rtn = false;
}
}
return rtn;
}
</script>
,當我在使用此驗證通常形成其工作,但在表模式的驗證碼不work..help我解決這個問題... TQ
視圖演示 http://jsfiddle.net/andricoga/u9eZz/
這哪裏是功能validasi()? – 2013-03-18 04:36:16
您應該在服務器端使用純PHP進行驗證。 Javascript可以由用戶修改。 (特別是爲了你使用它)。 – 2013-03-18 04:38:10