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我有分頁使用AJAX
2頁調用第二頁從數據庫中獲取的所有記錄，這樣的第一頁：
<script language="JavaScript">
var HttPRequest = false;
function doCallAjax(Mode,users_ID) {
HttPRequest = false;
if (window.XMLHttpRequest) { // Mozilla, Safari,...
HttPRequest = new XMLHttpRequest();
if (HttPRequest.overrideMimeType) {
HttPRequest.overrideMimeType('text/html');
}
} else if (window.ActiveXObject) { // IE
try {
HttPRequest = new ActiveXObject("Msxml2.XMLHTTP");
} catch (e) {
try {
HttPRequest = new ActiveXObject("Microsoft.XMLHTTP");
} catch (e) {}
}
}
if (!HttPRequest) {
alert('Cannot create XMLHTTP instance');
return false;
}
var url = 'AjaxDeleteRecord.php';
var pmeters = "tMode=" + Mode +
"&tusers_ID=" + users_ID;
HttPRequest.open('POST',url,true);
HttPRequest.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
HttPRequest.setRequestHeader("Content-length", pmeters.length);
HttPRequest.setRequestHeader("Connection", "close");
HttPRequest.send(pmeters);
HttPRequest.onreadystatechange = function()
{
if(HttPRequest.readyState == 3) // Loading Request
{
document.getElementById("mySpan").innerHTML = "Now is Loading...";
}
if(HttPRequest.readyState == 4) // Return Request
{
document.getElementById("mySpan").innerHTML = HttPRequest.responseText;
}
}
}
</script>
<body Onload="JavaScript:doCallAjax('LIST','');">
<form name="frmMain">
<div style="margin-right:10px">
<span id="mySpan"></span>
</div>
，第二頁是php，其獲取的數據：
$strMode = $_POST["tMode"];
$users_ID = $_POST["tusers_ID"];
if($strMode == "DELETE")
{
//$strSQL = "DELETE FROM users , stores WHERE users.users_StoreId=stores.stores_ID AND users.users_ID = '".$users_ID."'";
$strSQL = "update users set users_delete='1' where users.users_ID = '".$users_ID."'";
$objQuery = mysql_query($strSQL) or die (mysql_error());
}
$strSQL = "SELECT * FROM users , stores WHERE users.users_StoreId=stores.stores_ID and users.users_delete='0' ORDER BY stores.stores_Name , users.users_Type ASC ";
$objQuery = mysql_query($strSQL) or die ("Error Query [".$strSQL."]");
這個問題，我不能讓分頁工作。
任何人都可以幫助我嗎？
什麼是'HttP'？我只知道'HTTP'。 'javascript：'不屬於任何'onsomething'處理器。 – ThiefMaster
請檢查以下鏈接http://www.9lessons.info/2009/09/pagination-with-jquery-mysql-and-php.html這很簡單 – mymotherland
您正在使用[過時的數據庫API]（http：///stackoverflow.com/q/12859942/19068），並應使用[現代替換]（http://php.net/manual/en/mysqlinfo.api.choosing.php）。你也暴露了自己[SQL注入攻擊]（http://bobby-tables.com/），一個現代的API會使[防禦]更容易（http://stackoverflow.com/questions/60174/best-防止 - 注入 - 在PHP中）自己從。 – Quentin