Question

我有一個sample.xml中文件below..I需要掃描的項目「裁判後的「修改」標籤「內核/ MSM」和 打印字/heads"..i下面有一個sample.xml文件和xml輸出嗎？我可以稍後找出python部分，任何人都可以提供關於如何完成此操作的輸入？

輸入： -

Assume there is a variable project like below 

project='kernel/msm' 

sample.xml 

    <?xml version="1.0" encoding="utf-8"?> 
    <project name="platform/vendor/google/proprietary/code" 
      path="vendor/widevine" 
      revision="refs/heads/ab_mr" 
      x-grease-customer="none" 
      x-quic-dist="none" 
      x-ship="none" /> 
    <!-- test Projects --> 
    <project name="kernel/msm" 
      path="kernel" 
      revision="refs/heads/msm-3.4" 
      x-grease-customer="none" 
      x-quic-dist="la" 
      x-ship="oss" /> 
    ...... 

    EXPECTED OUTPUT:- 

    msm-3.4 

Sample code:- 

project='kernel/msm' 
#open xml file 
with open('./test.xml', 'r') as f: 
    #get the branch and project 
    for line in project : 
     if line in 'revision': 
      branch = line.split('/')[-1] 
print branch 

感謝

Answer 1

import xml.etree.ElementTree as ET 
import re 

temp = 'refs/heads/' 
name = 'kernel/msm' 

pattern = re.compile('%s(.*)' % temp) 
tree = ET.parse('sample.xml') 
root = tree.getroot() 

project = root.find("./project[@name='%s']" % name) 
revision = project.get('revision') 

res = pattern.match(revision) 
print(res.group(1)) 

你有一個根節點來包裝你的XML數據，例如<數據>否則將引發一個解析錯誤。