甲骨文執行查詢時,我創建了一個namedquery如下:奇怪的行爲與EclipseLink的
SELECT o
FROM TableName1Entity o , TableName2Entity a
WHERE o.field1 = a.field4
AND a.field5 = :param1
即轉換爲SQL語句:
SELECT TABLE_NAME1.FIELD1, TABLE_NAME1.FIELD2, TABLE_NAME1.FIELD3
FROM TABLE_NAME2 t0, TABLE_NAME1 t1
WHERE ((t0.FIELD4 = t1.FIELD1)
AND (t0.FIELD5 = ?));
,並返回ORA-00904: "TABLE_NAME1"."FIELD3": invalid identifier
但它工作時,我手動修改如下:(他們都按預期工作)
SELECT t1.FIELD1, t1.FIELD2, t1.FIELD3
FROM TABLE_NAME2 t0, TABLE_NAME1 t1
WHERE ((t0.FIELD4 = t1.FIELD1)
AND (t0.FIELD5 = ?));
SELECT TABLE_NAME1.FIELD1, TABLE_NAME1.FIELD2, TABLE_NAME1.FIELD3
FROM TABLE_NAME2 t0, TABLE_NAME1
WHERE ((t0.FIELD4 = TABLE_NAME1.FIELD1)
AND (t0.FIELD5 = ?));
SELECT FIELD1, FIELD2, FIELD3
FROM TABLE_NAME2 t0, TABLE_NAME1 t1
WHERE ((t0.FIELD4 = t1.FIELD1) AND (t0.FIELD5 = ?));
SELECT FIELD1, FIELD2, FIELD3
FROM TABLE_NAME2 t0, TABLE_NAME1
WHERE ((t0.FIELD4 = TABLE_NAME1.FIELD1)
AND (t0.FIELD5 = ?));
PS:出於安全原因,我不能給表或字段名稱。
事情是:當表名被明確設置以及標籤給它時,查詢不起作用。
請不要改變命名查詢 給替代解決方案,因爲它應該是罰款,是和更改命名查詢是不是 選項。除非它真的有錯誤。
你沒有表現出命名查詢;一個已命名的查詢屬於ORM的世界,並且不是寫入SQL(對於該表具有這種別名「標籤」的SQL)。看看[什麼是命名查詢](http://stackoverflow.com/questions/4517069/what-is-a-named-query) – 2012-07-10 13:43:41
和JPA的實現是?因爲將JPQL查詢轉換爲SQL與實現 – DataNucleus 2012-07-10 15:07:50
JPA 1.0.2與EclipseLink 1.1.1 – w35l3y 2012-07-10 16:42:11