使用具有數組的數組變量修改數組中的字符串

Question

我想循環使用幾個for循環來調用每個數組項。我遇到了一些麻煩，只是把正確的代碼拉下來。我曾嘗試使用數組的全局定義等。

var An = new Array(   
     "11111100011111",  
     "11111000011111",  
     "11110011001111", 
     "11100000000111", 
     "11001111110011", 
     "10011111111001"); 
var Bn = new Array(   
     "1000000001",  
     "1001111001",  
     "1000000001", 
     "1000000001", 
     "1001111001", 
     "1000000001"); 

// This second part sits in a onload function. 
var alphabet = "AB".split(""); 

for (x = 0; x < 6; x++) {  
    for (i = 0; i < 2; i++) { 
    var my_object = {}; 
    my_object = window[alphabet[x] + 'n[' + i + ']']; 
    my_object = window[my_object].replace(/0/g, "B"); 
    my_object = window[my_object].replace(/1/g, "_"); 
    } 
} 

Answer 1

你應該做的是把An和Bn成一個對象。這將使它更容易很多稍後參考。

var alphabet = { 
    An: [ 
     "11111100011111",  
     "11111000011111",  
     "11110011001111", 
     "11100000000111", 
     "11001111110011", 
     "10011111111001" 
    ], 
    Bn: [ 
     "1000000001",  
     "1001111001",  
     "1000000001", 
     "1000000001", 
     "1001111001", 
     "1000000001" 
    ] 
}; 

然後你挑出你想要的數組並循環。

var arrays = ['A', 'B']; 
for(var x = 0, xLen = arrays.length; x < xLen; x++){ 
    var my_key = arrays[x]+'n'; 
    for(var i = 0, iLen = alphabet[my_key].length; i < iLen; i++){ 
     alphabet[my_key][i] = alphabet[my_key][i].replace(/0/g, "B"); 
     alphabet[my_key][i] = alphabet[my_key][i].replace(/1/g, "_"); 
    } 
} 

實際上，對於內for循環，你也可以使用Array.map。

var arrays = ['A', 'B']; 
for(var x = 0, xLen = arrays.length; x < xLen; x++){ 
    var my_key = arrays[x]+'n'; 
    alphabet[my_key] = alphabet[my_key].map(function(val){ 
     val = val.replace(/0/g, "B"); 
     val = val.replace(/1/g, "_"); 
     return val; 
    }); 
}