如何獲得一個變量，然後在Python中沒有空格的字符串

Question

所以我做了這個，它的工作原理，但我有點挑剔，所以我希望它工作100％。這是代碼

import random 
input_1 = str(input("Do you want to roll a dice? Enter y for yes anything else for no. ")) 
if input_1 == "y": 
    dicesides = int(input("How many sides do you want your dice to have? ")) 
    diceroll = random.randint(1, dicesides) 
    print("The dice rolled a",diceroll ".") 
    input_2 = str(input("Do you want to roll the dice again? Same keys. ")) 
    while input_2 == "y": 
     print(random.randint(1, dicesides)) 
     input_2 = str(input("Do you want to roll the dice again? Same keys. ")) 
    else: 
     print("Okay, goodbye now.") 

else: 
    print("Okay, goodbye now.") 

當代碼運行時，它告訴我它「滾動」的數字，但它在數字後面留出空格。我不想要這種行爲。 當我發現我將如何改變第二個+骰子到它。

想通了，謝謝！

Answer 1

查看print函數的幫助頁面。如果給出了一個參數列表，它會打印它們，參數爲sep，默認情況下爲單個空格。所以：

print("This",1,"is",2,"spaced",3,"out.") 
print("This",1,"is",2,"not.",sep="") 

將表現不同。你會想用sep=""並添加自己的尾隨或前導空格手動你的字符串，像這樣：

print("You rolled a ", roll, ".", sep="")