如何檢查Oracle中的所有無效同義詞

Question

我有表user_synonyms，我可以在其中查看名稱，表和表所有者。有沒有辦法看看這個同義詞是否仍然有效，例如，如果引用表仍然存在而沒有手動嘗試它？

Answer 1

您可以通過加入ALL_TABLES來檢查表是否存在（同義詞可能不在同一模式的表中）。

select * 
    from all_synonyms s 
    left outer join all_tables t 
    on s.table_owner = t.owner 
    and s.table_name = t.table_name 
where s.owner = user 

添加條件and t.table_name is null如果您想要那些表不存在的同義詞。

如果要檢查同義詞是否爲VALID查詢ALL_OBJECTS。

select * 
    from all_synonyms s 
    join all_objects o 
    on s.owner = o.owner 
    and s.synonym_name = o.object_name 
where o.object_type = 'SYNONYM' 
    and s.owner = user 
    and o.status <> 'VALID' 

---

由於a_horse_with_no_name在評論中指出，有一個同義詞是一個表，視圖，序列連包裝都是有效的沒有要求。

所以，你可能要更改第一個查詢查找這些還有：

select * 
    from all_synonyms s 
    join all_objects o 
    on s.table_owner = o.owner 
    and s.table_name = o.object_name 
where s.owner = user 

Answer 2

使用下面的查詢：

select s.table_owner, s.table_name 
from all_synonyms s, all_tables t 
where s.table_owner = t.owner(+) 
and s.table_name = t.table_name(+) 
and t.owner is null 
--s.owner = 'SCHEMA_NAME' 
; 

Answer 3

select distinct os.* 
from all_objects os 
     ,all_synonyms s 
where 1 = 1 
and os.object_type = 'SYNONYM' 
and os.STATUS  = 'INVALID' 
and os.object_name = s.synonym_name 
and not exists  (select unique(1) 
         from all_objects o1 
         where o1.object_name = s.TABLE_NAME 
         and o1.owner  = s.TABLE_OWNER) 
order by 2;