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Question

當我運行命令

subprocess.call(['intersectBed','-u','-a',out_snv_filter,'-b',cds,'>',out_cds],shell=True) 

我得到彙報的解釋爲intersectBed的幫助菜單。

但是當我運行

>>> ' '.join(['intersectBed','-u','-a',out_snv_filter,'-b',cds,'>',out_cds]) 
'intersectBed -u -a test/test.out.snv.filter -b gencode7.cds.bed > test/test.out.cds' 

$ intersectBed -u -a test/test.out.snv.filter -b gencode7.cds.bed > test/test.out.cds 

程序正常運行。這裏有什麼不同？

Answer 1

from subprocess import check_call 

args = ['intersectBed','-u','-a',out_snv_filter,'-b',cds] 
with open(out_cds, 'wb') as outfile: 
    check_call(args, stdout=outfile)