如何處理目錄的文件名中的一個批處理文件

Question

我想列出最新的目錄文件夾不使用單詞「補丁」

for /f "tokens=*" %%a in ('dir /b /od') do (  
    // some if loop to ensure that newest is not set to something that ends with "-patch". 
set newest=%%a 
) 

Answer 1

for /f "delims=" %%a in ('dir /b /s /o-d /ad ^|findstr /v /e /c:"-patch" 2^>nul') do (   
set "newest=%%~fa" 
goto :break 
) 
:break 
echo newest : %newest% 

Answer 2

setlocal enableextensions 
for /f "tokens=*" %%a in ('dir /b /od') do (
    set "a=%%a" 
    if /i not "!a:~-5!"=="patch" set "file=%%a" 
) 

結束file將包含所需的文件夾名稱。

Answer 3

試試這個：

for /f "delims=" %%a in ('dir /b /od /ad ^|findstr /evi "patch" 2^>nul') do set "RecentFolder=%%~a" 
echo %RecentFolder%