好吧,這真令人沮喪。我使用我的API密鑰非常好。身份驗證沒有問題,令牌生成良好,會話密鑰也可以。發送HTTP POST請求時無效的方法簽名
但是,當我運行playlist.create
,播放列表不會創建。
我今天幾乎從零開始,重新編寫了大部分代碼。我成功創建了16個播放列表,沒有錯誤。但今天,相同的代碼無法正常工作。我根本沒有碰它,但錯誤。
private static void buildPlaylist() {
String mood = "Happy";
System.out.println("\nMood is " + mood + "\n\n");
String title = URLEncoder.encode(mood + " " + new Date().getTime(), "UTF-8");
String description = URLEncoder.encode("For when you are " + mood + ". Created by MoodicPlayer.", "UTF-8");
MessageDigest md = MessageDigest.getInstance("MD5");
String apiSig = "api_key" + key + "description" + description + "methodplaylist.createsk" + sessionKey + "title" + title + secret;
md.update(apiSig.getBytes());
byte byteData[] = md.digest();
//convert the byte to hex format
StringBuffer sb = new StringBuffer();
for (int i = 0; i < byteData.length; i++) {
sb.append(Integer.toString((byteData[i] & 0xff) + 0x100, 16).substring(1));
}
String hashedSig = sb.toString();
// FOR DEBUGGING
System.out.println("api_key = " + key);
System.out.println("api_sig = " + hashedSig);
System.out.println("session key = " + sessionKey);
// FOR DEBUGGING
String urlParameters = "method=playlist.create&api_key="+ key + "&api_sig=" + hashedSig + "&description=" + description + "&sk=" + sessionKey + "&title=" + title;
String request = "http://ws.audioscrobbler.com/2.0/";
URL url = new URL(request);
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setDoOutput(true);
connection.setDoInput(true);
connection.setInstanceFollowRedirects(false);
connection.setRequestMethod("POST");
connection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
connection.setRequestProperty("charset", "utf-8");
connection.setRequestProperty("Content-Length", "" + Integer.toString(urlParameters.getBytes().length));
connection.setUseCaches(false);
DataOutputStream wr = new DataOutputStream(connection.getOutputStream());
wr.writeBytes(urlParameters);
wr.flush();
wr.close();
InputStream is = null;
Scanner s = null;
try {
if (connection.getResponseCode() != 200) {
s = new Scanner(connection.getErrorStream());
} else {
is = connection.getInputStream();
s = new Scanner(is);
}
s.useDelimiter("\\Z");
String response = s.next();
System.out.println("\nResponse: " + response + "\n\n");
BufferedWriter out = new BufferedWriter(new FileWriter("requestCreate.xml"));
out.write(response);
out.close();
} catch (IOException e2) {
e2.printStackTrace();
}
// FOR DEBUGGING
try {
System.out.println("Response Code: " + connection.getResponseCode());
System.out.println("Response Message: " + connection.getResponseMessage());
} catch (IOException e) {
e.printStackTrace();
}
// FOR DEBUGGING
connection.disconnect();
}
和輸出:
Starting test for creating playlist...
Mood is Happy
api_key = xxxxx
api_sig = xxxxxx
session key = xxxxx
Response: <?xml version="1.0" encoding="utf-8"?>
<lfm status="failed">
<error code="13">
Invalid method signature supplied
</error>
</lfm>
Response Code: 403
Response Message: Forbidden
我檢查了代碼,但找不到任何錯誤。我的意思是16小時前的代碼很好,突然不工作了!
出於安全考慮,我無法向您顯示我的安全密鑰。但是,我確實編寫了一個快速程序來查找last.fm會話密鑰:http://github.com/thekarangoel/LastFMSessionKeyFinder只需在last.fm/api註冊,在程序中輸入您的API密鑰和密鑰,即可獲得測試API調用所需的所有內容。
它看起來像你寫你的URL參數代入實體主體。他們不應該成爲網址的一部分嗎? – Pace 2013-04-09 18:34:41
我不這麼認爲,因爲這是一個POST請求。 – 2013-04-09 19:42:41