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我轉換函數從MATLAB到C++,需要一個矢量並分離到含有600個值並在200。這裏的時間間隔改變的塊是函數(在Matlab):將矢量拆分成塊 - 這是正確的嗎?
function f = block(v, N, M)
% This function separates the vector
% into blocks. Each block has size N.
% and consecutive blocks differ in
% their starting positions by M
%
% Typically
% N = 30 msec (600 samples)
% M = 10 msec (200 samples)
n = length(v);
maxblockstart = n - N + 1;
lastblockstart = maxblockstart - mod(maxblockstart-1 , M);
% Remove the semicolon to see the number of blocks
% numblocks = (lastblockstart-1)/M + 1
numblocks = (lastblockstart-1)/M + 1;
f = zeros(numblocks,N);
for i = 1:numblocks
for j = 1:N
f(i,j) = v((i-1)*M+j);
end
端
而在C++函數:
vector<iniMatrix> Audio::something(vector<double>& theData, int N, int M)
{
//How many blocks of size N can we get?
int num_blocks = theData.size()/N;
int n = theData.size();
int maxblockstart = n - N;
int lastblockstart = maxblockstart - (maxblockstart % M);
int numbblocks = (lastblockstart)/M + 1;
this->width = N;
//Create the vector with enough empty slots for num_blocks blocks
vector<iniMatrix> blocked(num_blocks);
//Loop over all the blocks
for(int i = 0; i < num_blocks; i++) {
//Resize the inner vector to fit this block
blocked[i].resize(N);
//Pull each sample for this block
for(int j = 0; j < N; j++) {
blocked[i][j] = theData[i*N+j];
}
}
return blocked;
}
這是否看起來是正確的?我知道這是一個奇怪的問題,我可能會得到負面反饋,但是,我試着計算過零點的數量,並顯示錯誤的答案,所以,我如何分解矢量可能有問題。
編輯:
iniMatrix是2D矢量的一個typedef
可生產96塊(含600個值)
blocked [i] [j] = theData [i * N + j]; N是錯字? –
@DanilAsotsky你是什麼意思? 「blocked [i] [j] = theData [i * N + j];」是不是一個錯字..有沒有錯誤? – Phorce
你在Matlab代碼(代碼中的最後一個循環)中有v((i-1)* M + j),但是在C++代碼中它是數據[i * N + j]。似乎有誤印,可能導致錯誤。例如,你需要有數據[i * M + j]。 –