Google地理編碼。解析JSON問題

我想從他們的郵政編碼（加拿大/美國）的谷歌地理編碼中獲得用戶所在的城市，州/省，國家/地區。我檢索數據爲JSON：https://developers.google.com/maps/documentation/geocoding/#JSON Google地理編碼。解析JSON問題

問題是，並不總是相同的數量/順序的'address_components'。我正在使用就像：$geocodedinfo['results'][0]['address_components'][3]['short_name']; 但我很快意識到，這並不總是省/國家，因爲有時谷歌會在'address_components'下添加一個額外的元素。

有沒有一種方法來解析結果只是爲了我需要的細節（即：城市，州/省，國家）？

編輯當我得到它json_decode($result, true)

Array 
(
[results] => Array 
    (
     [0] => Array 
      (
       [address_components] => Array 
        (
         [0] => Array 
          (
           [long_name] => V2X 2P6 
           [short_name] => V2X 2P6 
           [types] => Array 
            (
             [0] => postal_code 
            ) 

          ) 

         [1] => Array 
          (
           [long_name] => Maple Ridge 
           [short_name] => Maple Ridge 
           [types] => Array 
            (
             [0] => locality 
             [1] => political 
            ) 

          ) 

         [2] => Array 
          (
           [long_name] => Maple Ridge 
           [short_name] => Maple Ridge 
           [types] => Array 
            (
             [0] => administrative_area_level_3 
             [1] => political 
            ) 

          ) 

         [3] => Array 
          (
           [long_name] => Greater Vancouver Regional District 
           [short_name] => Greater Vancouver Regional District 
           [types] => Array 
            (
             [0] => administrative_area_level_2 
             [1] => political 
            ) 

          ) 

         [4] => Array 
          (
           [long_name] => British Columbia 
           [short_name] => BC 
           [types] => Array 
            (
             [0] => administrative_area_level_1 
             [1] => political 
            ) 

          ) 

         [5] => Array 
          (
           [long_name] => Canada 
           [short_name] => CA 
           [types] => Array 
            (
             [0] => country 
             [1] => political 
            ) 

          ) 

        ) 

       [formatted_address] => Maple Ridge, BC V2X 2P6, Canada 
       [geometry] => Array 
        (
         [bounds] => Array 
          (
           [northeast] => Array 
            (
             [lat] => 49.2214351 
             [lng] => -122.6577849 
            ) 

           [southwest] => Array 
            (
             [lat] => 49.219268 
             [lng] => -122.663613 
            ) 

          ) 

         [location] => Array 
          (
           [lat] => 49.2202679 
           [lng] => -122.660587 
          ) 

         [location_type] => APPROXIMATE 
         [viewport] => Array 
          (
           [northeast] => Array 
            (
             [lat] => 49.2217005303 
             [lng] => -122.6577849 
            ) 

           [southwest] => Array 
            (
             [lat] => 49.2190025697 
             [lng] => -122.663613 
            ) 

          ) 

        ) 

       [types] => Array 
        (
         [0] => postal_code 
        ) 

      ) 

    ) 

[status] => OK 
)

來源

2012-10-05 cantaffordretail

我使用的是XML而不是JSON，但我必須迭代，直到找到需要的數據。 –

我有同樣的問題，但冷杉我的情況下，我最需要的address_components所以我用foreach（）得到我想要的，忘記其餘的。 –

@ayeshk是否有可能遍歷數組，並獲取['long_name']值WHERE ['types'] ['0'] =='country'for isntance？我從來沒有這樣做過。 – cantaffordretail

你將不得不遍歷結果我居然解碼JSON。
大部分相關的PHP函數都不支持多維數組，並且無論如何都會循環。

你可能會想是這樣的：

foreach ($geocodedinfo["results"] as $result) { 
    foreach ($result["address_components"] as $address) { 
     // Repeat the following for each desired type 
     if (in_array("country", $address["types"])) { 
      $country = $address["long_name"]; 
     } 
    } 
}

來源

2012-10-05 22:34:00 Sara

這正是我所需要的。現在我知道in_array函數。謝謝。 – cantaffordretail

嘗試尋找這個，http://php.net/manual/en/control-structures.foreach.php它是遍歷數組，你可以這樣做，

foreach ($result['results'][0]['address_components'] as $key => $val) 
    { 
    if (in_array('country', $result['results'][0]['address_components'][$key]['types'][0])) 
    { 
    echo $result['results'][0]['address_components'][$key]['long_name']; 
    } 
}

類似的東西應該工作

來源

2012-10-05 22:35:29 King

這將無法捕捉'types'中的值的順序不同，即'[「political」，「country」] - 您將要使用'in_array'。 – Sara

編輯我的答案來解決這個問題。 – King

您可以通過循環運行結果foreach並獲取要查找的數據。

我對Google類型的含義進行了最佳猜測，我可能會忽略這些。

$translate = array(
    'locality' => 'city', 
    'administrative_area_level_3' => 'area', // not sure what this one is 
    'administrative_area_level_2' => 'county', // regional district ? 
    'administrative_area_level_1' => 'state', // province 
    'country' => 'country', 
    'postal_code' => 'zip', // postal code 
); 

$address_components = array(); 
foreach ($geocodedinfo['results'][0]['address_components'] as $component) { 
    $address_components[$translate[$component['type'][0]]] = $component['long_name']; 
} 

var_dump($address_components);

來源

2012-10-05 22:39:20 Benjam

-1

//解析JSON響應 $jsondata = json_decode($data,true); $results = $jsondata['results'][0]; $addr =$results['formatted_address'];

這允許您訪問長格式的地址

326倫敦路，紐伯裏，伯克希爾，西伯克郡RG14 2DA，英國

來源

2013-10-09 20:41:03 user1973273

Google地理編碼。解析JSON問題

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