WAJP基於依據給定的年齡，其顯示了不同的信息年齡

Question

WAJP程序顯示消息。以下是可能的響應：

age is less than 16, say "You can't drive."

age is less than 18, say "You can't vote."

age is less than 25, say "You can't rent a car."

age is 25 or over, say "You can do anything that's legal."

這裏有一個樣品運行。請注意，一個人誰是16歲以下將顯示三個消息，一個16，一個是下了也正在18之下，一個25

Answer 1

4基本if-statements下，也正在將解決這個問題，只要你想如果年齡輸入滿足四個要求中的任何一個，則輸出所有可能的消息。

import java.util.Scanner; 

public class main { 
    public static void main(String[] args) { 
     Scanner scan = new Scanner(System.in); 

     System.out.println("Enter an age: "); 
     int age = Integer.parseInt(scan.nextLine()); 

     if (age < 16) 
     { 
      System.out.println("You can't drive."); 
     } 
     if (age < 18) 
     { 
      System.out.println("You can't vote."); 
     } 
     if (age < 25) 
     { 
      System.out.println("You can't rent a car."); 
     } 
     if (age >= 25) 
     { 
      System.out.println("You can do anything that's legal."); 
     } 
    } 
}