snackbar.show（）不是在的setAction

Question

snackbar = Snackbar.make(getWindow().getDecorView().getRootView(),"Please check your internet connection", Snackbar.LENGTH_INDEFINITE) 
      .setAction("RETRY", new View.OnClickListener() { 
       @Override 
       public void onClick(View view) { 
        snackbar.show(); 
       } 
      }); 

工作OnClick的重試行動我想再次表現出同樣的Snackbar.But它不工作！

Answer 1

您必須在onClick之外寫下snackbar.show();，如下所示。

Snackbar snackbar = Snackbar 
    .make(coordinatorLayout, "No internet connection!", Snackbar.LENGTH_LONG) 
    .setAction("RETRY", new View.OnClickListener() { 
     @Override 
     public void onClick(View view) { 
     } 
    }); 


View sbView = snackbar.getView(); 
TextView textView = (TextView) sbView.findViewById(android.support.design.R.id.snackbar_text); 
textView.setTextColor(Color.YELLOW); 
snackbar.show(); 

Answer 2

final Snackbar snackbar = Snackbar.make(getWindow().getDecorView().getRootView(),"Please check your internet connection", Snackbar.LENGTH_INDEFINITE); 
     snackbar.setAction("RETRY", new View.OnClickListener() { 
      @Override 
      public void onClick(View view) { 
      ConnectivityManager manager = (ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE); 
      NetworkInfo connection = manager.getActiveNetworkInfo(); 
      if (connection != null && connection.isConnectedOrConnecting()){ 
       snackbar.dismiss(); 
      } 
      else{ 
       snackbar.show(); 
      } 
      } 
      }); 
      snackbar.show(); //add here to show snackbar 

Answer 3

public static boolean isNetworkAvailable(final Context context) { 
     final ConnectivityManager connectivityManager = ((ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE)); 
     return connectivityManager.getActiveNetworkInfo() != null && connectivityManager.getActiveNetworkInfo().isConnected(); 
    } 

void ShowSnackBar(){ 


     Snackbar snackbar = Snackbar 
       .make(coordinatorLayout,"Check internet connection", Snackbar.LENGTH_LONG) 
       .setAction("Retry", new View.OnClickListener() { 
        @Override 
        public void onClick(View view) { 

         // Write Retry Code like making api call here 

        // apiCall(); 



        } 
       }); 

snackbar.show();  
} 

if(!isNetworkAvailable()){ 
ShowSnackBar(); 
} 

Answer 4

據我所知，你不能重新顯示的小吃店與在小吃吧的行動。下面是使用按鈕彈出快餐欄的示例。希望能幫助到你。

Answer 5

有報道這樣的錯誤。請看看here。所以直到錯誤修復發佈之前，您必須展示另一個快餐欄。所以總共你必須有兩個snacbars。示例如下

private void showFirstSnackbar(View view) 

     final Snackbar snackbar = Snackbar.make(view, "Please check your internet connection", Snackbar.LENGTH_INDEFINITE); 
     snackbar.setAction("RETRY", new View.OnClickListener() { 
        @Override 
        public void onClick(View view) { 
         snackbar.dismiss(); 
         showAnotherSnackBar(view); 
        } 
       }); 
} 


private void showAnotherSnackBar(View view){ 
    final Snackbar snackbar = Snackbar.make(view, "Please check your internet connection", Snackbar.LENGTH_INDEFINITE); 
     snackbar.setAction("RETRY", new View.OnClickListener() { 
        @Override 
        public void onClick(View view) { 
         snackbar.dismiss(); 
         showFirstSnackbar(view); 
        } 
       }); 
} 

給出試試這個，讓我知道，如果還有問題

Answer 6

void ShowSnackBar(){ 
     Snackbar snackbar = Snackbar 
       .make(coordinatorLayout,"Check internet connection", Snackbar.LENGTH_LONG) 
       .setAction("Retry", new View.OnClickListener() { 
        @Override 
        public void onClick(View view) { 

         if(isNetworkAvailable){ 
          ///called api 
         }else{ 
          ShowSnackBar(); 
          } 
        } 
       }); 

snackbar.show();  
} 
if(!isNetworkAvailable()){ 
ShowSnackBar(); 
}