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我的問題如下: 我的程序的目的:重複從另一個excel文件中的數據3次,然後再轉到下一組數據。 例如 所需的輸出:在excel中重複行無法使用這組代碼
23 25 27
23 25 27
23 25 27
28 4 21
28 4 21
28 4 21
我當前(誤差)輸出是: 例如 錯誤輸出:
23 25 27
28 4 21
我的代碼如下。爲什麼我不能僅僅通過重複代碼並相應地更改行號來爲列K,L和M重複我的代碼3次?它顯示錯誤輸出而不是所需的輸出。 :( 非常感謝你的閱讀和幫助!
#>>>>>>>>>>>SEPERATE LIST SHOWN IN PYTHON PROGRAM (i.e. dataX, data Y, data Z), -START- <<<<<<<<<<<<<<<#
CRS=[]
dataX=[sheet.cell_value(1, col) for col in range(sheet.ncols)]
dataY=[sheet.cell_value(2, col) for ju in range(4)for col in range(sheet.ncols)]
dataBin = [sheet.cell_value(6, col) for col in range(sheet.ncols)]
for nm in range (int(ND)): #for nm in range of ND
CRS.append((dataX[nm+6],dataY[nm+6],dataBin[nm+6]))
print CRS
print ""
workbook = xlwt.Workbook()
sheet = workbook.add_sheet('sheet1')
for index, value in enumerate(dataBin):
sheet.write(3, index, value)
sheet.write(1, index, value)
sheet.write(2, index, value)
(下續)#ERROR最有可能從這裏開始
for np in range(int(ND)):
#COLUMN K = X COORDINATE
sheet1.write(np+30,10,CRS[np][0]) #np+30 == row. 10== column K
sheet1.write(np+31,10,CRS[np][0]) #np+31 == row. 11== column K,
sheet1.write(np+32,10,CRS[np][0]) #np+32 == row. 12== column K
#COLUMN L = Y COORDINATE
sheet1.write(np+30,11,CRS[np][1]) #np+30 == row. 10 == column L
sheet1.write(np+31,11,CRS[np][1]) #np+31 == row. 11 == column L
sheet1.write(np+32,11,CRS[np][1]) #np+32 == row. 12 == column L
#COLUMN M = SOFT BIN
sheet1.write(np+30,12,CRS[np][2]) #np+30 == row. 10 == column M
sheet1.write(np+31,12,CRS[np][2]) #np+31 == row. 11 == column M
sheet1.write(np+32,12,CRS[np][2]) #np+32 == row. 12 == column M
乘以NP感謝您的幫助很大!通過創建一個循環,我發現了另一種方法。即np + = 3,而不是必須3次。但我仍然會給你打勾:) – Sandy