未捕獲的參考錯誤：$未定義獲取方法

Question

function s() 
{ 
    alert("hello"); 
    $email = document.getElementById("inp_subscribe").value; 
    alert($email); 
    $.get("subscribe.php",{inp_subscribe: $email },""); 
    alert($email); 
} 

請幫我學習如何使$.get()函數正常工作。

Answer 1

試試這個代碼...

function s() { 
 
    alert("hello"); 
 
    var $email = document.getElementById("inp_subscribe").value; 
 
    alert($email); 
 
    $.get("subscribe.php",{inp_subscribe: $email },""); 
 
    alert($email); 
 
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> 
 

 
<label for="inp_subscribe">Email:</label> 
 
<input name="inp_subscribe" id="inp_subscribe" type="email"/> 
 
<button onclick="s();">Submit</button>