Sed。如何在下一個變線，以特定模式

Question

我的文件是：

DIVIDER 
Sometext_string 

many 
lines 
of random 
text 
DIVIDER 
Another_Sometext_string 
many 
many 
lines 
DIVIDER 
Third_sometext_string 
.... 

如何改變線以下除法模式

結果必然是：

DIVIDER 
[begin]Sometext_string[end] 

many 
lines 
of random 
text 
DIVIDER 
[begin]Another_Sometext_string[end] 

many 
many 
lines 
DIVIDER 
[begin]Third_sometext_string[end] 

.... 

Answer 1

可能，這將有助於 -

sed '/DIVIDER/{n;s/.*/[begin]&[end]\n/;}' file1 

執行：

[jaypal:~/Temp] cat file1 
DIVIDER 
Sometext_string 

many 
lines 
of random 
text 
DIVIDER 
Another_Sometext_string 
many 
many 
lines 
DIVIDER 
Third_sometext_string 

[jaypal:~/Temp] sed '/DIVIDER/{n;s/.*/[begin]&[end]\n/;}' file1 
DIVIDER 
[begin]Sometext_string[end] 


many 
lines 
of random 
text 
DIVIDER 
[begin]Another_Sometext_string[end] 

many 
many 
lines 
DIVIDER 
[begin]Third_sometext_string[end] 

UPDATE：

這個版本將處理第一分後，一個空行。

[jaypal:~/Temp] sed -e '0,/DIVIDER/{n;s/.*/[begin]&[end]/;}' -e '/DIVIDER/{n;s/.*/[begin]&[end]\n/;}' file1 
DIVIDER 
[begin]Sometext_string[end] 

many 
lines 
of random 
text 
DIVIDER 
[begin]Another_Sometext_string[end] 

many 
many 
lines 
DIVIDER 
[begin]Third_sometext_string[end] 

[jaypal:~/Temp] 

更新2：

有沒有其他問題，現在讓我想我會提供一個替代解決方案awk如果你喜歡？ :)

awk '/DIVIDER/{print;getline;sub(/.*/,"[begin]&[end]");print;next}1' file1 

[jaypal:~/Temp] awk '/DIVIDER/{print;getline;sub(/.*/,"[begin]&[end]\n");print;next}1' file1 
DIVIDER 
[begin]Sometext_string[end] 


many 
lines 
of random 
text 
DIVIDER 
[begin]Another_Sometext_string[end] 

many 
many 
lines 
DIVIDER 
[begin]Third_sometext_string[end] 

[jaypal:~/Temp] 

這種處理第一個空白分割線後 -

[jaypal:~/Temp] awk '/DIVIDER/{count++;print;getline;if(count==1) sub(/.*/,"[begin]&[end]");else sub(/.*/,"[begin]&[end]\n");print;next}1' file1 
DIVIDER 
[begin]Sometext_string[end] 

many 
lines 
of random 
text 
DIVIDER 
[begin]Another_Sometext_string[end] 

many 
many 
lines 
DIVIDER 
[begin]Third_sometext_string[end] 

[jaypal:~/Temp]