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我有一個下拉列表是leavetype在此sickleave,緊急請假類型,當我選擇數據庫值緊急請假去病假即在數據庫下拉列表在asp.net
leasid leavedescription leavetypeid:
1 abcdefe 1
那裏,因爲我在選擇2表格
錯誤在哪裏?
這是
cc.leavee(Txt_leaveValue, Convert.ToInt32(leavedrop.SelectedValue));
和
LMS.leavetype le = new LMS.leavetype();
DropDownList2.DataSource = le.getdep();
DropDownList2.DataValueField = "leaveID";
DropDownList2.DataTextField = "leavetypeID";
DropDownList2.DataBind();
是的,我忘了添加此代碼如果(!page.ispostback) –
太棒了!現在「接受」我的答案,我們都會很高興:) – egrunin
hahahahha ....:D –