正確地將輸出格式化爲文件

Question

我正在解析URL並將它們保存到文件中。我的代碼工作正常的Windows，但在Ubuntu它增加了一個小「U」每一行

import re 

reports = "C:\Users/_____/Desktop/Reports/" 
string = "Here is a string to test. http://www.blah.com & http://2nd.com" 
url_match = re.findall(r'(https?://[^\s]+)', string) 
print url_match 

if url_match != []: 
    with open(reports + "_URLs.txt", "a") as text_file: 
     text_file.write('{}'.format(url_match).replace(',', "\n").replace('[', '').replace(']', '').replace("'", '').replace(' ', '').__add__("\n")) 

的前面有沒有人對如何解決這種想法？謝謝

Answer 1

'{}'.format(url_match)將url_match列表變成其人類可讀的字符串，然後您使用一些複雜的字符串替換回到要寫入的行的列表。沿着這條線你會得到一個unicode字符串，因此就是'u'。我不會去猜測爲什麼發生這種情況，因爲真正的解決辦法是隻處理列表：

import re 

# reports = "C:\Users/_____/Desktop/Reports/" 
reports = "" # for test 
string = "Here is a string to test. http://www.blah.com & http://2nd.com" 
url_match = re.findall(r'(https?://[^\s]+)', string) 
print url_match 
if url_match: 
    with open(reports + "_URLs.txt", "a") as text_file: 
     for url in url_match: 
      text_file.write(url + '\n')