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以下代碼允許用戶在鏈接上滾動時顯示div。問題是,當用戶滾動鏈接時div不會消失。無論如何,我們可以做到這一點,當用戶滾動鏈接的div消失,但用戶仍然能夠把他們的光標下來,並與在div中的項目進行交互.....任何幫助將不勝感激。問題與DIV顯示/隱藏代碼?
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title>Untitled Document</title>
<script type='text/javascript'>
/* <![CDATA[ */
document.getElementsByClassName = function(){
if(arguments.length == 1)
arguments[1]='*';
var retnode = [];
var myclass = new RegExp('\\b'+arguments[0]+'\\b');
var elem = this.getElementsByTagName(arguments[1]);
for(var i = 0; i < elem.length; i++){
var classes = elem[i].className;
if(myclass.test(classes))
retnode.push(elem[i]);
};
return retnode;
};
window.onload=function(){
var x = document.getElementsByClassName('HoverMe', 'a');
for(var i = 0; i < x.length; i++){
x[i].onmouseover=function(){
var m = document.getElementsByClassName('HoverMe', 'a');
var n = document.getElementsByClassName('showMe', 'div');
for(var i = 0; i<m.length; i++){
n[i].style.display = (m[i]==this)?'block':'none';
};
};
};
x = document.getElementsByClassName('showMe','div');
for(var i = 0; i < x.length; i++){
x[i].style.display = 'none';
};
};
/* ]]> */
</script>
</head>
<body>
<a class='HoverMe'>link 1</a><a class='HoverMe'>link 2</a>
<div class='showMe'>stuff 1</div><div class='showMe'>stuff 2</div>
</body>
</html>
這是真棒!但無論如何,我們可以這樣做,以便當用戶將鼠標移到出現的div上時,它們可以與該div上的內容進行交互,而不會消失? – 2012-08-11 18:52:19