Java：如何創建SOAP請求？

Question

我有一個wsdl和xsd文件，並希望在python上創建SOAP請求到web服務器。我從來沒有用過肥皂，所以我的問題可能很簡單，但我花了四個小時，並沒有找到解決方案。

我嘗試了兩種方法：Android上的低級請求和KSOAP2。

WSDL

<wsdl:message name="<some request>"> 
    <wsdl:part element="txh:<some request>" name="parameters"/> 
</wsdl:message> 
<wsdl:message name="<some response>"> 
    <wsdl:part element="txh:<some response>" name="parameters"/> 
</wsdl:message> 

XSD

<xs:element name=""<some request>"> 
    <xs:annotation> 
     <xs:documentation>"<text>"</xs:documentation> 
    </xs:annotation> 
    <xs:complexType> 
     <xs:sequence> 
      <xs:element name="mode" type="response-mode"/> 
     </xs:sequence> 
    </xs:complexType> 
</xs:element> 
<xs:element name="<some response>"> 
    <xs:complexType> 
     <xs:annotation> 
      <xs:documentation>"<text>"</xs:documentation> 
     </xs:annotation> 
     <xs:sequence> 
      <xs:element ref="<text>"/> 
      <xs:element name="<another text>" minOccurs="0"> 
       <xs:complexType> 
        <xs:sequence> 
         <xs:element name="<name a>" type="xs:int"/> 
         <xs:element name="<name b>" type="xs:int"/> 
         <xs:element name="<name c>" type="xs:int"/> 
        </xs:sequence> 
       </xs:complexType> 
      </xs:element> 
     </xs:sequence> 
    </xs:complexType> 
</xs:element> 

代碼在安卓

private final static String xml = "<?xml version=\"1.0\" encoding=\"utf-8\"?>\n" + 
         "<SOAP-ENV:Envelope " + 
         "xmlns:SOAP-ENV=\"http://schemas.xmlsoap.org/soap/envelope/\" " + 
         "xmlns:SOAP-ENC=\"http://schemas.xmlsoap.org/soap/encoding/\" " + 
         "xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" " + 
         "xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\">" + 
         "<SOAP-ENV:Header>" + 
         "</SOAP-ENV:Header>" + 
         "<SOAP-ENV:Body xmlns:ns1=\"<namespace>\">" + 
         " <xs:element name=\"<request>\"> " + 
         "<xs:annotation>" + 
          "<xs:documentation>"<text>"</xs:documentation>" + 
         "</xs:annotation>" + 
         "<xs:complexType>" + 
          "<xs:sequence>" + 
           "<xs:element name=\""<text>"\" type=\"response-mode\"/>" + 
          "</xs:sequence>" + 
         "</xs:complexType>" + 
        "</xs:element>" + 
         "</SOAP-ENV:Body>" + 
         "</SOAP-ENV:Envelope>"; 



public Entity execute(final String body) { 
    Log.d(TAG, "Start request "); 
    Entity result = new Entity(); 
    AndroidHttpClient client = AndroidHttpClient.newInstance(TAG); 
    HttpParams params = client.getParams(); 
    HttpConnectionParams.setConnectionTimeout(params, 10000); 
    HttpConnectionParams.setSoTimeout(params, 15000); 
    HttpProtocolParams.setUseExpectContinue(params, true); 

    HttpPost post = new HttpPost(url); 
    post.setParams(params); 
    post.setHeader("soapaction", NAMESPACE.concat("/").concat(METHOD)); 
    post.setHeader("Content-Type", "text/xml; charset-utf8"); 
    try { 
     String request = createRequest(xml); 
     HttpEntity entityToRequest = new StringEntity(request); 
     post.setEntity(entityToRequest); 
     Log.d(TAG, post.toString()); 

     HttpResponse response = client.execute(post); 
     final int status = response.getStatusLine().getStatusCode(); 
     if (HttpStatus.SC_OK == status) { 
      HttpEntity entity = response.getEntity(); 
      String str = EntityUtils.toString(entity); 
      Log.d(TAG, str); 
     } 

    } catch (UnsupportedEncodingException e) { 
     e.printStackTrace(); 
    } catch (IOException e) { 
     e.printStackTrace(); 
    } 

在這一請求，我得到一個500服務器代碼，所以我想在我的請求，問題。你認爲它形成良好嗎？

Answer 1

我找到了解決方案。 soupUI和類似的樂器可以幫助你理解你的肥皂使用結構。