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我NetDataContractSerializer似乎混淆:在XML年底出現了兩次:NetDataContractSerializer產生無效的XML

<?xml version="1.0" encoding="utf-8"?> 
<Project xmlns:i="http://www.w3.org/2001/XMLSchema-instance" z:Id="1" 

[...] 
     <d2p1:anyType i:nil="true" /> 
     </d2p1:_items> 
     <d2p1:_size>2</d2p1:_size> 
     <d2p1:_version>2</d2p1:_version> 
    </d2p1:items> 
    </ProjectParts> 
    <ProjectPath z:Id="31">D:\t10\</ProjectPath> 
</Project>ze> 
       <d2p1:_version>3</d2p1:_version> 
      </d2p1:items> 
      <d2p1:_monitor xmlns:d7p1="http://schemas.datacontract.org/2004/07/System.Collections.ObjectModel" z:Id="33"> 
       <d7p1:_busyCount>0</d7p1:_busyCount> 
      </d2p1:_monitor> 
      </Elements> 
      <Project z:Ref="1" i:nil="true" xmlns="http://schemas.datacontract.org/2004/07/Modules.WorkspaceManager.Types" /> 
     </d2p1:anyType> 
     <d2p1:anyType i:nil="true" /> 
     <d2p1:anyType i:nil="true" /> 
     </d2p1:_items> 
     <d2p1:_size>2</d2p1:_size> 
     <d2p1:_version>2</d2p1:_version> 
    </d2p1:items> 
    </ProjectParts> 
    <ProjectPath z:Id="34">D:\t10\</ProjectPath> 
</Project> 

正如你可以看到,有一些嚴重的口吃怎麼回事。它偶爾會發生,我不能重現錯誤。有任何想法嗎?這是否可能是由正在寫入的VS中打開的文件造成的?

序列化我的對象是這樣的:

private void SerializeToFile(object objectToSerialize) 
    { 
     Stream stream = null; 

     try 
     { 
      stream = File.Open(_fileName, FileMode.OpenOrCreate, FileAccess.Write); 
      using (var writer = XmlWriter.Create(stream, new XmlWriterSettings { Indent = true })) 
      { 
       NetDataContractSerializer serializer = new NetDataContractSerializer(); 
       serializer.WriteObject(writer, objectToSerialize); 
      } 
     } 

     finally 
     { 
      if (stream != null) stream.Close(); 
     } 
    } 

而且序列化的類看起來像這樣:

[DataContract(IsReference = true)] 
public class Project : IProject 
{ 
    [DataMember] public string ProjectPath { get; set; } 
    [DataMember] public string ProjectName { get; set; } 
    [DataMember] public Collection<IProjectPart> ProjectParts { get; set; } 

    public T GetPart<T>() where T : IProjectPart 
    { 
     return ProjectParts.OfType<T>().First(); 
    } 

    public void RegisterPart<T>(T part) where T : IProjectPart 
    { 
     if (ProjectParts.Any(p => p.GetType().IsInstanceOfType(part))) throw new InvalidOperationException("Part already registered."); 
     ProjectParts.Add(part); 
     part.Project = this; 
    } 

    public void Load() 
    { 
     foreach (var projectPart in ProjectParts) 
     { 
      projectPart.Load(); 
     } 
    } 

    public void Unload() 
    { 
     foreach (var projectPart in ProjectParts) 
     { 
      projectPart.Unload(); 
     } 
    } 

    public void Save() 
    { 
     foreach (var projectPart in ProjectParts) 
     { 
      projectPart.Save(); 
     } 
    } 

    public Project() 
    { 
     ProjectParts = new Collection<IProjectPart>(); 
    } 
} 

謝謝!

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可以你發佈你正在嘗試序列化的類,以及你如何做,等等? – tchrikch 2013-02-20 14:02:01

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@tchrikch:看我的編輯。謝謝你的評論。 – Marc 2013-02-20 14:07:03

回答

1

問題很簡單 - 當你反覆序列化你的對象時,你可以使用不同大小的IProjectPart集合。該File.Open方法不清除以前的內容文件,以便承擔下列步驟:

我)序列化對象有兩個IProjectPart instaces - 讓我們說,這將需要10行xml文件

II)序列化對象的再一個IProjectPart集合中的實例 - 這次將需要8行xml文件

iii)第9行和第10行將填充舊的xml數據,因爲它們在序列化嘗試之間未被清​​除 - 所以存在一些重複垃圾 - 尋找XML數據。

親身體驗一下,您會看到如何生成這些多個標籤。

注:8條10日線都是近似值爲我實現

注2:我建議使用using語句序列化方法裏面的流(爲所有IDisposable的對象):

private void SerializeToFile(object objectToSerialize) 
{ 
    using(var stream = File.Open(_fileName, FileMode.OpenOrCreate, FileAccess.Write)) 
    { 
     using (var writer = XmlWriter.Create(stream, new XmlWriterSettings { Indent = true })) 
     { 
      NetDataContractSerializer serializer = new NetDataContractSerializer(); 
      serializer.WriteObject(writer, objectToSerialize); 
     } 
    } 
} 
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啊!謝謝!我通過使用File.WriteAllText(_fileName,string.Empty)清理文件來修復它; ...非常感謝! – Marc 2013-02-20 15:09:32