我NetDataContractSerializer似乎混淆:在XML年底出現了兩次:NetDataContractSerializer產生無效的XML
<?xml version="1.0" encoding="utf-8"?>
<Project xmlns:i="http://www.w3.org/2001/XMLSchema-instance" z:Id="1"
[...]
<d2p1:anyType i:nil="true" />
</d2p1:_items>
<d2p1:_size>2</d2p1:_size>
<d2p1:_version>2</d2p1:_version>
</d2p1:items>
</ProjectParts>
<ProjectPath z:Id="31">D:\t10\</ProjectPath>
</Project>ze>
<d2p1:_version>3</d2p1:_version>
</d2p1:items>
<d2p1:_monitor xmlns:d7p1="http://schemas.datacontract.org/2004/07/System.Collections.ObjectModel" z:Id="33">
<d7p1:_busyCount>0</d7p1:_busyCount>
</d2p1:_monitor>
</Elements>
<Project z:Ref="1" i:nil="true" xmlns="http://schemas.datacontract.org/2004/07/Modules.WorkspaceManager.Types" />
</d2p1:anyType>
<d2p1:anyType i:nil="true" />
<d2p1:anyType i:nil="true" />
</d2p1:_items>
<d2p1:_size>2</d2p1:_size>
<d2p1:_version>2</d2p1:_version>
</d2p1:items>
</ProjectParts>
<ProjectPath z:Id="34">D:\t10\</ProjectPath>
</Project>
正如你可以看到,有一些嚴重的口吃怎麼回事。它偶爾會發生,我不能重現錯誤。有任何想法嗎?這是否可能是由正在寫入的VS中打開的文件造成的?
序列化我的對象是這樣的:
private void SerializeToFile(object objectToSerialize)
{
Stream stream = null;
try
{
stream = File.Open(_fileName, FileMode.OpenOrCreate, FileAccess.Write);
using (var writer = XmlWriter.Create(stream, new XmlWriterSettings { Indent = true }))
{
NetDataContractSerializer serializer = new NetDataContractSerializer();
serializer.WriteObject(writer, objectToSerialize);
}
}
finally
{
if (stream != null) stream.Close();
}
}
而且序列化的類看起來像這樣:
[DataContract(IsReference = true)]
public class Project : IProject
{
[DataMember] public string ProjectPath { get; set; }
[DataMember] public string ProjectName { get; set; }
[DataMember] public Collection<IProjectPart> ProjectParts { get; set; }
public T GetPart<T>() where T : IProjectPart
{
return ProjectParts.OfType<T>().First();
}
public void RegisterPart<T>(T part) where T : IProjectPart
{
if (ProjectParts.Any(p => p.GetType().IsInstanceOfType(part))) throw new InvalidOperationException("Part already registered.");
ProjectParts.Add(part);
part.Project = this;
}
public void Load()
{
foreach (var projectPart in ProjectParts)
{
projectPart.Load();
}
}
public void Unload()
{
foreach (var projectPart in ProjectParts)
{
projectPart.Unload();
}
}
public void Save()
{
foreach (var projectPart in ProjectParts)
{
projectPart.Save();
}
}
public Project()
{
ProjectParts = new Collection<IProjectPart>();
}
}
謝謝!
可以你發佈你正在嘗試序列化的類,以及你如何做,等等? – tchrikch 2013-02-20 14:02:01
@tchrikch:看我的編輯。謝謝你的評論。 – Marc 2013-02-20 14:07:03