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嗨我正在使用菜單來刪除列表視圖項目。
我有兩個菜單,一個是Delete
,另一個是Select All
。我正在從數據庫中檢索數據,並使用checkbox
在listview
中顯示它。
如果我選擇了某些列表項並選擇刪除,則必須刪除所選項目。如果我選擇從菜單中選擇全部,則必須選擇所有列表項,並且如果從菜單中選擇刪除,則必須刪除所有數據。
問題是如果我通過Select All
菜單選擇所有listview項目,並且我取消選中某些列表項目,剩下的選定項目不會被刪除。
我已使用ResourceCursorAdapter
來顯示數據庫中的列表項。使用Android中的菜單刪除列表視圖項目
private void CreateMenu(Menu menu) {
menu.setQwertyMode(true);
MenuItem mnu1 = menu.add(0, 0, 0, "Delete");
{
mnu1.setAlphabeticShortcut('a');
}
MenuItem mnu2 = menu.add(1, 1, 1, "Select All");
{
mnu2.setAlphabeticShortcut('s');
}
}
private boolean MenuChoice(MenuItem item) throws Exception {
switch (item.getItemId()) {
case 0:
if (getStrinValue != null) {
delhistory(getStrinValue);
} else {
Toast.makeText(getApplicationContext(),
"Please select an Item", Toast.LENGTH_SHORT).show();
}
case 1:
if (item.getTitle().equals("Select All")) {
for (int i = 0; i < lvhistory.getChildCount(); i++) {
RelativeLayout itemLayout = (RelativeLayout) lvhistory
.getChildAt(i);
final CheckBox cb = (CheckBox) itemLayout
.findViewById(R.id.check);
cb.setChecked(true);
if (cb.isChecked() == true) {
getStrinValue = getStrinValue + ","
+ cb.getTag().toString();
System.out.println("CHECKEDIITTEEMSS-->>>"
+ getStrinValue);
} else {
}
}
}
}
return false;
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
super.onCreateOptionsMenu(menu);
CreateMenu(menu);
return true;
}
@Override
public boolean onOptionsItemSelected(MenuItem item) {
try {
return MenuChoice(item);
} catch (Exception e) {
e.printStackTrace();
}
return false;
}
private class MyAdapter extends ResourceCursorAdapter {
public MyAdapter(Context context, Cursor cur) {
super(context, R.layout.custom_sent_view, cur);
}
@Override
public View newView(Context context, Cursor cur, ViewGroup parent) {
LayoutInflater li = (LayoutInflater) getSystemService(Context.LAYOUT_INFLATER_SERVICE);
return li.inflate(R.layout.custom_sent_view, parent, false);
}
@Override
public void bindView(View view, Context context, Cursor cur) {
TextView tvListText = (TextView) view.findViewById(R.id.Mobile);
chkBox = (CheckBox) view.findViewById(R.id.check);
tvListText.setText(cur.getString(cur
.getColumnIndex(MainscreenActivity.COL_Mobile)));
chkBox.setTag(cur.getString(cur
.getColumnIndex(MainscreenActivity.COL_Sent_id)));
chkBox.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
// TODO Auto-generated method stub
CheckBox cb = (CheckBox) v;
if (cb.isChecked() == true) {
getStrinValue = getStrinValue + ","
+ cb.getTag().toString();
} else {
getStrinValue = null;
}
}
});
}
}
public void delhistory(String getStrinValue) {
int pos1 = getStrinValue.indexOf(",");
if (pos1 > 0) {
String rowId = getStrinValue.substring(pos1 + 1);
String delimiter = "\\,";
String[] sentID = rowId.split(delimiter);
for (int i = 0; i < sentID.length; i++) {
String temp0 = sentID[i];
int id = Integer.parseInt(temp0);
MainscreenActivity.JEEMAAndroSMSDB
.delete(MainscreenActivity.Table_SentHistory, "_id="
+ id, null);
}
Toast.makeText(getApplicationContext(),
"History deleted successfully", Toast.LENGTH_SHORT).show();
finish();
Intent intent = new Intent(getApplicationContext(),
SentHistoryActivity.class);
startActivity(intent);
}
}
嘗試通過將getStrinValue初始化爲null,只要您將數據分配給它。 – user1203673 2012-08-09 06:15:15
''Log.info()''你的'getStrinValue'在'delHistory'中,看看哪些ID傳遞到刪除。 – 2012-08-09 06:17:53
@ user1203673我試過了,但它不工作。請檢查代碼嗎? – Manikandan 2012-08-09 06:29:00