字符串不斷重複，直到randint提供正確的答案。

Question

我想創建這個簡單的遊戲，但我遇到了麻煩。這是代碼，它不斷循環不同的答案。請原諒這個可怕的故事，有人可以幫忙嗎？

如果選項等於正確（答案），代碼應該很快。但它並沒有，它只是保持循環兩個選項，直到它達到正確的。

import random 


def options(): 
    print() 
    print("What do you do?") 
    print("1. Check the local bakery to see if the criminal is hiding in the oven.") 
    print("2. Search the forest to see if he's made a quick getaway.") 
    print("3. Check with the innkeeper to see if anyone has come in recently.") 
    print("4. Search the sewers, this criminal scum will do anything for money.") 
    print("9. Quit.") 



print("On a dark and rainy night the town of Ogalu was quietly sleeping. On this night, a criminal \nwas amidst the sleeping people he sought to steal the King's crown and make himself rich." 
     "The criminal named Zalox snuck into the palace, and stole the crown without alerting the guards. \nAfter this he ran away, but you, Bob the guard, heard something. You went to check the king" 
     "he was safe, you then went to check the crown. They were gone!, you alert the townsguard and set \nout to catch this criminal scum.") 
correct = random.randint(1,4) 
options() 
option = int(input("What option: ")) 
while option != 9: 
    if option == 1: 
     if correct == option: 
      print("You make your way into the local bakery, you hear something drop. You turn around and there he is, the theif, in the local oven. You arrest him and put him in jail!") 
     else: 
      print("As you search the bakery you think you hear something near the oven, as you check it out you realise it's just a mouse. The theif isn't here!") 

    elif option == 2: 
     if correct == 2: 
      print("As you make your way towards the forest you see a shadow limping away, it's the theif! You chase after him and catch him, you send him to jail for life!") 
      break 
     else: 
      print("You head towards the forest, you think you hear something moving in the bushes, as you check it out a giant wolf chases you out of the forest, the theif isn't here") 
    elif option == 3: 
     if correct == 3: 
      print("You approach the innkeeper and ask if anyone suspicious has been staying there, the innkeeper says a man came in recently in a hurry, he's in his room. You dart upstairs, burst into his room" 
        "and arrest him!") 
      break 
     else: 
      print("You see the innkeeper walking his dog, you ask if anyone suspicious has been stayig with him, he says no. The theif isn't here") 

    elif option == 4: 
     if correct == 4: 
      print("You search the old, dirty, smelly sewers looking for the thief, in the distance you see a light and a person running. It's the thief! You take a shortcut and pounce on him! You put him to jail!") 
      break 
     else: 
      print("As you search the sewers you see nothing but smelly, dirty, sewage. Maybe the theif won't do anything for money. This was a bad idea, you make your way out the next exit") 

print("Congratulatious! You saved the King's crown by capturing the theif know as Zalox. He's sentanced to life in jail. The town can finally relax again! You are know as Hero of Ogalu!") 

Answer 1

您做出的更改option的價值循環條件，而只是分配給該名稱的循環之外：

option = int(input("What option: ")) 
while option != 9: 

移動它的while循環，而不是內（也確保option的初始分配滿足while循環的條件！）。

此外，不請自來的建議：一旦你利用dict離子的力量，你將被吹走。這真是太棒了。將這些選項映射到要調用的字符串或對象或函數，並且可能更清晰和/或更具可擴展性。