2017-08-14 119 views
0

在document.ready上,我的數據表相應地加載。jquery數據表填充搜索數據

我需要做的是構建一個功能,在用戶進行搜索時重新載入數據表。

所以DataTable中加載這樣的:

$(document).ready(function() 
{ 
    $('#searchSubmit').on('click', function() // used for searching 
    { 
    var searchbooking = $('#searchbooking').val(); 
    var searchquote = $('#searchquote').val(); 
    var searchtli = $('#searchtli').val(); 

    if(searchbooking == "" && searchquote == "" && searchtli == "") 
    { 
     $('.message').text('You did not enter any search criteria.'); 
     return false; // making sure they enter something 
    } 
    else 
    { 
     $.post('api/searchAll.php', {searchbooking:searchbooking, searchquote:searchquote, searchtli:searchtli}, function(data) 
     { 
     // what do i do here??? 
     // how do I get the return results to load 
     }); 
    } 
    }); 
    // if the user does not enter any search parameters, load everything 
    $('#example1').DataTable({  
    "ajax": { 
     "url": "api/displayQnams.php", 
     "type": "POST", 
     "dataSrc": '' 
    }, 
    "columns": [ 
     { "data": "" }, 
     { "data": "column1" }, 
     { "data": "column2" }, 
     { "data": "column3" } 
    ], 
    "iDisplayLength": 25, 
    "order": [[ 6, "desc" ]], 
    // and so on 
    }); 
}); 

正如你會在上面的代碼中看到,當文檔準備好,如果用戶不進行搜索,我加載所有從數據過程稱爲'displayQnams.php'。

但是,如果用戶進行搜索,參數將被髮送到另一個名爲'qnamsSearch.php'的進程。

如何使用'qnamsSearch.php'中的搜索結果重新加載數據表?

我試圖創建從后里面的變量:

var dataUrl = data; 

我試圖調用Ajax調用該變量:

"ajax": { 
    "url": dataUrl, 
    "type": "POST", 
    "dataSrc": '' 
} 

但數據表將不顯示任何東西,有沒有控制檯錯誤。

我該如何做這項工作?

預先感謝您。

回答

0

你可以嘗試使用這個。

用戶點擊搜索按鈕後,下面是流動:

  1. 清除數據表 - datatables clear()
  2. 添加新數據表 - datatables rows.add()
  3. 調整列大小(可選) - datatables adjust.columns()
  4. 用新數據重新繪製數據表 - datatables draw()

    $(document).ready(function(){ 
        var datatable = $('#example1').DataTable({  
         "ajax": { 
          "url": "api/displayQnams.php", 
          "type": "POST", 
          "dataSrc": '' 
         }, 
         "columns": [ 
          { "data": "" }, 
          { "data": "column1" }, 
          { "data": "column2" }, 
          { "data": "column3" } 
         ], 
         "iDisplayLength": 25, 
         "order": [[ 6, "desc" ]] 
        }); 
    
        $('#searchSubmit').on('click', function(){ 
         var searchbooking = $('#searchbooking').val(); 
         var searchquote = $('#searchquote').val(); 
         var searchtli = $('#searchtli').val(); 
    
         if(searchbooking == "" && searchquote == "" && searchtli == ""){ 
          $('.message').text('You did not enter any search criteria.'); 
          return false; // making sure they enter something 
         } else { 
          $.post(
           'api/searchAll.php', 
           { searchbooking:searchbooking, searchquote:searchquote, searchtli:searchtli }, 
           function(data) { 
            var newData = data; 
            datatable.clear().draw(); 
            datatable.rows.add(newData); // Add new data 
            datatable.columns.adjust().draw(); // Redraw the DataTable 
           }); 
          } 
         }); 
    }); 
    
+0

我收到一個錯誤消息:datatable未定義。有什麼想法嗎? –