MVC3下拉列表控件不保持狀態，爲什麼？

Question

我有一個下拉上的局部視圖列表控制和張貼下拉列表控制的狀態不能維持

下面是部分視圖CSHTML代碼的形式後：

@model MvcApplication1.Models.TestCriteriaConsolidated 


@using (Html.BeginForm("Results", "Home")) 
{ 
<div style="float:left"> 
       <div style="font-weight:bold">     
        @Html.LabelFor(m => m.testCriteria.Year) 
       </div> 
       <div style="width:110px; "> 
        @Html.DropDownListFor(m => m.testCriteria.Year, new SelectList(new[] 
        { 

         new SelectListItem{ Text="All Years", Value=" " }, 
         new SelectListItem{ Text="2010", Value="2010" }, 
         new SelectListItem{ Text="2009", Value="2009" }, 
         new SelectListItem{ Text="2008", Value="2008" }, 
         new SelectListItem{ Text="2007", Value="2007" }, 
         new SelectListItem{ Text="2006", Value="2006" } 

        }, "Value", "Text", "1"), new { @style = "width: 100px; margin-top: 5px" })   
       </div> 
      </div> 

      <div style="float:left"> 
       <div>     
        &nbsp; 
       </div> 
       <div style="width:100px; ">         
        <input type="submit" value="Results" /> 
       </div> 
      </div> 

}

這裏是我的CONTROLER代碼：

public ActionResult Index() 
    {      
     return View(); 
    } 

    public ActionResult Results() 
    { 
     string year = Request.Form["testCriteria.Year"]; 

     List<TestCriteriaResults> test = new List<TestCriteriaResults>(); 

     test.Add(new TestCriteriaResults { Value1 = "one", Value2 = "one", Value3="three", Value4="Four" }); 
     test.Add(new TestCriteriaResults { Value1 = "one", Value2 = "two", Value3="three", Value4="four" }); 
     test.Add(new TestCriteriaResults { Value1 = "one", Value2 = "two", Value3 = "three", Value4 = "four" }); 
     test.Add(new TestCriteriaResults { Value1 = "one", Value2 = "two", Value3 = "three", Value4 = "four" }); 
     test.Add(new TestCriteriaResults { Value1 = "one", Value2 = "two", Value3 = "three", Value4 = "four" });   

     TestCriteriaConsolidated combined = new TestCriteriaConsolidated(); 
     combined.testCriteriaResults = test; 

     return PartialView(combined); 
    } 

新型改性動作方法（這仍然沒有保持狀態）：

public ActionResult Results() 
    { 
     string year = Request.Form["testCriteria.Year"]; 


     List<TestCriteriaResults> test = new List<TestCriteriaResults>(); 

     test.Add(new TestCriteriaResults { Value1 = "one", Value2 = "one", Value3="three", Value4="Four" }); 
     test.Add(new TestCriteriaResults { Value1 = "one", Value2 = "two", Value3="three", Value4="four" }); 
     test.Add(new TestCriteriaResults { Value1 = "one", Value2 = "two", Value3 = "three", Value4 = "four" }); 
     test.Add(new TestCriteriaResults { Value1 = "one", Value2 = "two", Value3 = "three", Value4 = "four" }); 
     test.Add(new TestCriteriaResults { Value1 = "one", Value2 = "two", Value3 = "three", Value4 = "four" });   

     TestCriteriaConsolidated combined = new TestCriteriaConsolidated(); 
     TestCriteria criteria = new TestCriteria() { Year = year }; 

     combined.testCriteriaResults = test; 
     combined.testCriteria = criteria; 

     return PartialView(combined); 
    } 

Answer 1

下面的代碼創建你的下一個局部視圖，視圖模型：

TestCriteriaConsolidated combined = new TestCriteriaConsolidated(); 
combined.testCriteriaResults = test; 

您需要在此型號上設置年份：

combined.testCriteria.Year = Request.Form["testCriteria.Year"]; 

Answer 2

combined.testCriteria.Year需要獲得與您發佈

形式值設置

試試這個

[HttpPost] 
    public ActionResult Results(TestCriteriaConsolidated form) 
    { 
     List<TestCriteriaResults> test = new List<TestCriteriaResults>(); 
     test.Add(new TestCriteriaResults { Value1 = "one", Value2 = "one", Value3 = "three", Value4 = "Four" }); 
     test.Add(new TestCriteriaResults { Value1 = "one", Value2 = "two", Value3 = "three", Value4 = "four" }); 
     test.Add(new TestCriteriaResults { Value1 = "one", Value2 = "two", Value3 = "three", Value4 = "four" }); 
     test.Add(new TestCriteriaResults { Value1 = "one", Value2 = "two", Value3 = "three", Value4 = "four" }); 
     test.Add(new TestCriteriaResults { Value1 = "one", Value2 = "two", Value3 = "three", Value4 = "four" }); 

     TestCriteria criteria = new TestCriteria() { Year = form.testCriteria.Year }; 

     TestCriteriaConsolidated combined = new TestCriteriaConsolidated 
               { 
                testCriteriaResults = test, 
                testCriteria = criteria 
               }; 
     return View(combined); 
    } 

    public ActionResult Results() 
    { 
     return View(new TestCriteriaConsolidated()); 
    }