2014-10-10 38 views
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我有這個json編碼數據使用'服務器端'版本的數據表。 但是,如何將這個值放入數據表中,以便我的數據可以以表格形式列出?json編碼數據到數據表

{"sEcho":0,"iTotalRecords":"40","iTotalDisplayRecords":"40","aaData":[["[email protected]","5656565","656565"],["[email protected]","5656565","656565"],["[email protected]","5656565","656565"],["[email protected]","Greater Noida","201308"],["[email protected]","Greater Noida","201308"],["[email protected]","Greater Noida","201308"],["[email protected]","656","56"],["[email protected]","656","56"],["[email protected]","656","56"],["[email protected]","Lucknow","226005"],["[email protected]","Lucknow","226005"],["[email protected]","Lucknow","226005"],["[email protected]","Greater Noida","201308"],["[email protected]","Greater Noida","201308"],["[email protected]","Greater Noida","201308"],["[email protected]","Lucknow","226005"],["[email protected]","Lucknow","226005"],["[email protected]","Lucknow","226005"],["[email protected]","Lucknow","226005"],["[email protected]","Lucknow","226005"],["[email protected]","Lucknow","226005"],["[email protected]","Lucknow","226005"],["[email protected]","56565","56565"],["[email protected]","Greater Noida","201308"],["[email protected]","Greater Noida","201308"],["[email protected]","Greater Noida","201308"],["[email protected]","Greater Noida","201308"],["[email protected]","Lucknow","226005"],["[email protected]","Lucknow","226005"],["[email protected]","ko","koko"],["[email protected]","ko","koko"],["[email protected]","Greater Noida","201308"],["[email protected]","Lucknow","226005"],["[email protected]","o","ok"],["[email protected]","TA","TA"],["[email protected]","Lucknow","226012"],["[email protected]","Lucknow","226012"],["[email protected]","Lucknow","226012"],["[email protected]","o","ok"],["[email protected]","o","ok"]]} 
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問題沒有意義,不是表格構成'表格格式? – charlietfl 2014-10-10 19:39:30

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由於某種原因,它沒有。沒有表格,只有json被回顯。 – user2619381 2014-10-10 19:41:40

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記錄的插件方法的哪部分不起作用呢? – charlietfl 2014-10-10 19:42:38

回答

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$obj = json_decode($json); 

將創建與您的數據的對象

你也可以創建一個數組,但uusing真正的第二個參數

$array= json_decode($json, true);