你應該定義一個虛擬的CSS類像
.unsortable{}
然後調用的jqGrid替換默認items: '.jqgrow'參數與
jQuery("#list").jqGrid('sortableRows', { items: '.jqgrow:not(.unsortable)'});
現在你應該只添加類「不可排序」對行的sortableRows方法，你不希望被排序。讓我們在網格行中輸入ids'C28011'和'C28015'。然後，這樣做既可以使用的jqGridsetRowData方法或調用jQueryaddClass方法直接：
jQuery("#list").setRowData ('C28011', false, 'unsortable');
jQuery("#C28015",jQuery("#list")[0]).addClass('unsortable');
修訂（添加代碼示例）：看了您的評論後，我想如果我會更好在這裏發佈一個代碼示例：
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head id="Head">
<title>Demonstration of disabling sortableRows on some jqGrid rows</title>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<link rel="stylesheet" type="text/css" href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8.1/themes/redmond/jquery-ui.css" />
<link rel="stylesheet" type="text/css" href="http://www.ok-soft-gmbh.com/jqGrid/jquery.jqGrid-3.6.5/css/ui.jqgrid.css" />
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8.1/jquery-ui.min.js"></script>
<script type="text/javascript" src="http://www.ok-soft-gmbh.com/jqGrid/jquery.jqGrid-3.6.5/js/i18n/grid.locale-en.js"></script>
<script type="text/javascript" src="http://www.ok-soft-gmbh.com/jqGrid/jquery.jqGrid-3.6.5/js/jquery.jqGrid.min.js"></script>
<style type="text/css">
#sortable { list-style-type: none; margin: 0; padding: 0; width: 60%; }
#sortable li { margin: 0 3px 3px 3px; padding: 0.4em; padding-left: 1.5em; font-size: 1.4em; height: 18px; }
#sortable li span { position: absolute; margin-left: -1.3em; }
.unsortable {}
</style>
<script type="text/javascript">
//<![CDATA[
jQuery(document).ready(function() {
jQuery("#sortable").sortable({ items: 'li:not(.unsortable)'});
jQuery("#sortable").disableSelection();
jQuery("#sortrows").jqGrid({
datatype: 'local',
colNames:['Inv No','Date', 'Client', 'Amount','Tax','Total','Notes'],
colModel:[
{name:'id',index:'id', width:55},
{name:'invdate',index:'invdate', width:90},
{name:'name',index:'name asc, invdate', width:100},
{name:'amount',index:'amount', width:80, align:"right"},
{name:'tax',index:'tax', width:80, align:"right"},
{name:'total',index:'total', width:80,align:"right"},
{name:'note',index:'note', width:250, sortable:false}
],
rowNum:10,
width:700,
rowList:[10,20,30],
pager: '#psortrows',
sortname: 'invdate',
viewrecords: true,
sortorder: "desc",
caption:"Sortable Rows Example"
});
jQuery("#sortrows").jqGrid('sortableRows', { items: '.jqgrow:not(.unsortable)'});
var myData = [
{id: "11", invdate: "2007-10-06", name: "Client 1", amount: "600.00", tax:"120.00", total: "720.00", note: "not sortable"},
{id: "9", invdate: "2007-10-06", name: "Client 1", amount: "200.00", tax:"40.00", total: "240.00", note: "not sortable"},
{id: "5", invdate: "2007-10-05", name: "Client 3", amount: "100.00", tax:"0.00", total: "100.00", note: "not sortable"},
{id: "7", invdate: "2007-10-05", name: "Client 2", amount: "120.00", tax:"12.00", total: "134.00", note: "no tax at all"},
{id: "6", invdate: "2007-10-05", name: "Client 1", amount: "50.00", tax:"10.00", total: "60.00", note: ""},
{id: "4", invdate: "2007-10-04", name: "Client 3", amount: "150.00", tax:"0.00", total: "150.00", note: "no tax"}
];
for (var i = 0; i < myData.length; i++) {
jQuery("#sortrows").addRowData(myData[i].id, myData[i]);
}
jQuery("#sortrows").setRowData ('11', false, 'unsortable');
jQuery("#sortrows").setRowData ('9', false, 'unsortable');
jQuery("#5",jQuery("#sortrows")[0]).addClass('unsortable');
});
//]]>
</script>
</head>
<body>
<div class="demo">
<ul id="sortable">
<li class="ui-state-default unsortable"><span class="ui-icon ui-icon-arrowthick-2-n-s"></span>Item 1 (not sortable)</li>
<li class="ui-state-default unsortable"><span class="ui-icon ui-icon-arrowthick-2-n-s"></span>Item 2 (not sortable)</li>
<li class="ui-state-default"><span class="ui-icon ui-icon-arrowthick-2-n-s"></span>Item 3 (sortable)</li>
<li class="ui-state-default"><span class="ui-icon ui-icon-arrowthick-2-n-s"></span>Item 4 (sortable)</li>
<li class="ui-state-default"><span class="ui-icon ui-icon-arrowthick-2-n-s"></span>Item 5 (sortable)</li>
<li class="ui-state-default"><span class="ui-icon ui-icon-arrowthick-2-n-s"></span>Item 6 (sortable)</li>
<li class="ui-state-default"><span class="ui-icon ui-icon-arrowthick-2-n-s"></span>Item 7 (sortable)</li>
</ul>
</div>
<table id="sortrows"></table>
<div id="psortrows"></div>
</body>
</html>
在這段代碼中我使用在開始標準的jQuery排序功能允許只排序選定的項目。比我在jqGrid中做同樣的事情。你可以在這裏看到這個例子http://www.ok-soft-gmbh.com/jqGrid/sortableRows.htm。因此，在行中添加一個虛擬類「unsortable」後禁用「可排序」功能。刪除此類別開關「可排序」。您可以隨時爲選定的網格行或所有網格（jQuery("tr",jQuery("#list")[0]).addClass('unsortable');）執行此操作。
，你應該不會忘記的唯一的事情：在網格中添加數據後，你應該叫setRowData或addClass，例如，jqGrid的的loadComplete函數中。
UPDATED 2：請參閱the answer，其中描述瞭如何禁用網格特定行的排序。它使用更新版本的jqGrid和jQuery UI中存在的可能性。
謝謝。我喜歡你的方法，因爲它用一行代碼完成所有的事情，但是確實犧牲了Oleg的獨立行的粒度。 – 2012-08-03 00:01:57