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有一個id問題和choiecs數據庫和一個答案(多選)我想顯示它的所有數據庫中的左邊有一個複選框。最後我會提交一個提交按鈕,並且我想要在表格下顯示所有問題。我的嘗試。必須有一個更簡單的方法。謝謝!如何從數據庫中選擇行並用複選框顯示它們?
$result = mysqli_query($con,"SELECT id,question,choiceA,choiceB,choiceC,choiceD,answer FROM q_and_a ");
echo "<table border='1'>
<tr>
<th>Add</th>
<th>#</th>
<th>Question</th>
<th>A</th>
<th>B</th>
<th>C</th>
<th>D</th>
<th>Answer</th>
</tr>";
echo '<form method="POST" action="makeTest.php">';
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo '<td><input type="checkbox" name="questions[]" value="yes"></td>';
echo "<td>" . $row['id'] . "</td>";
echo "<td>" . $row['question'] . "</td>";
echo "<td>" . $row['choiceA'] . "</td>";
echo "<td>" . $row['choiceB'] . "</td>";
echo "<td>" . $row['choiceC'] . "</td>";
echo "<td>" . $row['choiceD'] . "</td>";
echo "<td>" . $row['answer'] . "</td>";
echo "</tr>";
}
echo "</table>";
?>
請問涉及的jQuery intrest你的解決方案? – jiy 2014-10-27 16:51:57