用字符串回答Stdin

Question

我已經嘗試了很多不同的方法來獲得此代碼的工作。

任何人都知道如何得到這個工作？

import sys 

y = 1 

def test(): 
    print("Hello?") 
    x = (sys.stdin.readline()) 
    if x == ("hello"): 
     print("Ah your back") 
    else: 
     print("Huh?") 

while y == 1: 
     test() 

Answer 1

這應該工作：

import sys 

y = 1 

def test(): 
    print("Hello?") 
    x = (sys.stdin.readline()) 
    if x == ("hello\n"): 
     print("Ah your back") 
    else: 
     print("Huh?") 

while y == 1: 
    test() 

你缺少這標誌着在字符串中一行的末尾的\n或換行符。

Answer 2

它在最後讀取\n的行，所以比較失敗。嘗試類似：

import sys 

y = 1 

def test(): 
    print("Hello?") 
    x = (sys.stdin.readline()) 
    if x[:-1] == ("hello"): 
     print("Ah your back") 
    else: 
     print("Huh?") 

while y == 1: 
     test() 

Answer 3

剝去換行符。

import sys 

def test(): 
    print("Hello?") 
    x = sys.stdin.readline().rstrip('\n') 
    if x == "hello": 
     print("Ah your back") 
    else: 
     print("Huh?") 

while True: 
     test() 

Answer 4

import sys 

y = 1 
def test(): 
    print("Hello?") 
    x = sys.stdin.readline() 
    if x == "hello\n": #either strip newline from x or compare it with "hello\n". 
     print("Ah your back") 
    else: 
     print("Huh?") 
test() #your while will cause stack overflow error because of infinite loop. 

http://ideone.com/Csbpn9

Answer 5

爲什麼不使用input()？當這可能是最簡單的方法...

import sys 

y = 1 

def test(): 
    print("Hello?") 
    x = input() 
    if x == ("hello"): 
     print("Ah your back") 
    else: 
     print("Huh?") 

while y == 1: 
     test()