3
傳遞一個列名稱,而不是索引問題代碼:在sqlite3的
NSString *query = @"SELECT Name FROM Category";
sqlite3_stmt *statement;
if (sqlite3_prepare_v2(database, [query UTF8String], -1, &statement, nil)
== SQLITE_OK) {
while (sqlite3_step(statement) == SQLITE_ROW) {
char *row =(char *)sqlite3_column_text(statement,0);
char *rowData = (char *)sqlite3_column_text(statement,1);
NSString *fieldName = [[NSString alloc] initWithUTF8String:row];
NSString *fieldValue = [[NSString alloc] initWithUTF8String:rowData];
NSLog(@"%@",fieldName);
NSLog(@"%@",fieldValue);
[fieldName release];
[fieldValue release];
}
sqlite3_finalize(statement);
}
char *row =(char *)sqlite3_column_text(statement,0);
在上面的代碼,而不是0不能只是通過一個列名? 我該怎麼做?