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我目前正在嘗試編寫一個基於文本的hang子手。如果你選擇猜測一封信,程序會在執行第53行後突然結束。請告訴我爲什麼會發生這種情況,因爲我無法弄清楚。Java程序突然在NetBeans中結束
這是我的一些Java代碼:
package hangman;
import java.util.Random;
import java.util.Scanner;
import java.lang.String;
public class Hangman {
public static void main(String[] args) {
// TODO code application logic here
Scanner chez = new Scanner(System.in);
Scanner waffle = new Scanner(System.in);
Random randomGenerator = new Random();
StringBuilder displayWord = new StringBuilder("______________________________");
String theWord = null;
String preLetter;
//String sbDisplayWord;
char letter = 0;
int randomNumber;
int lengthOfWord;
int numberOfLetterInWord = 0;
int gDisplay;
int guessWordNumber = 0;
String guessWord;
RandomWord troll = new RandomWord();
randomNumber = randomGenerator.nextInt(12);
//Fill var with the word.
theWord = troll.wordDecide(randomNumber);
System.out.println ("Welcome to Hangman!");
lengthOfWord=theWord.length();
System.out.println("This word has " + lengthOfWord + " letters.");
System.out.println("You have 20 guesses.");
for (int g =19; g >= 0; g--) {
System.out.println("If you want to guess the word, type 0. If you want to guess a letter, type 1.");
guessWordNumber=chez.nextInt();
if (guessWordNumber==0) {
System.out.println("Enter the word now. Remember, don't capitalize it.");
guessWord=waffle.nextLine();
if (guessWord.equals(theWord)) {
System.out.println("YOU WIN");
System.exit(0);
} else {
System.out.println("Sorry, this wasn't the correct word.");
}
} else if (guessWordNumber==1) {
System.out.println("Please enter the letter you wish to guess with.");
//System.out.println("It will tell you if you have guessed right for any of the letters. If it is blank, that means none of the letters match.");
preLetter=chez.nextLine();
if (preLetter.length()>0) {
letter=preLetter.charAt(0);
} else {
System.exit(0);
}
System.out.println("");
for(int i = 0; i <= lengthOfWord -1; i++) { //-Eshan
if (letter == theWord.charAt(i)) {
numberOfLetterInWord=i+1;
System.out.println("This letter matches with letter number " + numberOfLetterInWord + " in the word.");
displayWord.setCharAt(i, letter);
} else {
numberOfLetterInWord=i+1;
System.out.println("This letter doesn't match with letter number " + numberOfLetterInWord + " in the word.");
}
}
System.out.println("");
System.out.println("The word so far is " + displayWord);
System.out.println("");
gDisplay = g + 1;
System.out.println("You have " + gDisplay + " guesses left.");
} else {
System.exit(0);
}
}
System.out.println("GAME OVER");
System.exit(0);
}
}
這是我的Java代碼的另一部分:
package hangman;
public class RandomWord {
private static String[] wordArray = {
"psychology",
"keratin",
"nostalgia",
"pyromaniac",
"chlorophyl",
"derivative",
"unitard",
"pterodactyl",
"xylophone",
"excommunicate",
"obituary",
"infinitesimal",
"concupiscent",
};
public String wordDecide(int randomNumber) {
String theWord;
theWord = wordArray[randomNumber];
return theWord;
}
}
上碼偶聯的評述。 RandomWord不應該需要隨機數參數。單詞數組的大小僅在「RandomWord」內部是已知的,所以隨機數字應該在'RandomWord'內部生成,如'randomNumber = Random.nextInt(wordArray.size)'中所示,並且不作爲參數傳遞。 – 2013-04-11 03:03:07