Python的同時枚舉

錯誤從數組中刪除：Python的同時枚舉

Traceback (most recent call last): 
    File "<string>", line 10, in <module> 
    File "/Users/georg/Programmierung/Glyphs/Glyphs/Glyphs/Scripts/GlyphsApp.py", line 59, in __iter__ 
    File "/System/Library/Frameworks/Python.framework/Versions/2.7/Extras/lib/python/PyObjC/objc/_convenience.py", line 589, in enumeratorGenerator 
    yield container_unwrap(anEnumerator.nextObject(), StopIteration) 
objc.error: NSGenericException - *** Collection <__NSArrayM: 0x7f9906245480> was mutated while being enumerated.

我知道，因爲我想從數組中刪除的對象，同時還列舉這些對象出現此錯誤。但我不知道如何解決它。我對面向對象的編程還很陌生，並且將自己限制爲腳本編寫。

我搜索了網頁，它似乎解決了錯誤，我必須複製數組之前刪除對象。當我綁到前for path in thisLayer.paths:

但在這種情況下，我得到以下錯誤權的陣列通過deepcopy的

import copy 
pathcopy = copy.deepcopy(thisLayer.paths)

複製：

Cannot pickle Objective-C objects

一般先雕文後的程序崩潰。澄清：我在Glyphsapp（一款Typedesigning軟件）工作。

這裏是代碼：

# loops through every Glyph and deletes every path with nodes on the left half 
    for myGlyph in Glyphs.font.glyphs: 
     glname = myGlyph.name 
     thisLayer = Glyphs.font.glyphs[glname].layers[1] 
     middle = thisLayer.bounds.size.width/2+thisLayer.LSB 
     thisGlyph = thisLayer.parent 

     for path in thisLayer.paths: # this is where the code crashes 
      for thisNode in path.nodes: 
       if thisNode.position.x < middle: 
        #print thisNode.position.x 
        try: 
         thisLayer = path.parent() 
        except Exception as e: 
         thisLayer = path.parent 
        try: 
         thisLayer.removePath_ (thisNode.parent()) 
        except AttributeError: 
         pass

預先感謝您

來源

2016-02-11 Kai

您可以將要刪除的項目收集到一個單獨的列表中，然後使用另一個循環來覆蓋該列表以在thisLayer中刪除它們。 –

非常感謝您安德烈亞斯，

在您的幫助，我能夠解決我的代碼:-)

結果如下：

for myGlyph in Glyphs.font.glyphs: 
    glname = myGlyph.name 
    thisLayer = Glyphs.font.glyphs[glname].layers[1] 
    middle = thisLayer.bounds.size.width/2+thisLayer.LSB 
    thisGlyph = thisLayer.parent 

    for path in thisLayer.paths:  
     for thisNode in path.nodes: 
      if thisNode.position.x < middle: 
       nodeList = [] 
       nodeList.append(thisNode.parent()) 
    nLCopy = nodeList[:] 
    for ncontainer in nLCopy: 
     thisLayer.removePath_ (ncontainer)

來源

2016-02-12 11:18:11 Kai

Python的同時枚舉

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