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Question

可能重複解析嵌套的JSON：
Nested json to php search listing

我試圖解析一些JSON，我現在把一切都在一個頁面上分析，但其過多信息放在一個頁面上，我希望能夠通過列出父對象「教會」來過濾，然後一旦父母被點擊，我想孩子（嵌套）對象「軌道」被列出（基本上是爲了過濾通過JSON），（想想你的iPod你點擊一個藝術家（這是「chur CH「），那麼這張專輯（這是」專輯），然後選擇曲目（這是在JSON‘軌道’）

讓我怎麼做一個父對象是JSON解析的一個新的水平有關係嗎？

，您可以訪問http://ggcc.tv/JSON_Parsers/Music.php，看看有什麼我到目前爲止

請幫忙，謝謝。

PHP： http://www.godsgypsychristianchurch.net/music.json'; $ content = file_get_contents（$ filepath）; $ json = json_decode（$ content，true）;

$count = 0; 
    foreach ($json['rows'] as $row) { 
     ++$count; 

     echo "<h1>Row: {$count}</h1>"; 
     echo "Album: {$row[doc]['album']}<br />"; 
     echo "Church: {$row[doc]['church']}<br />"; 
     echo "Description: {$row[doc]['des']}<br />"; 
     echo "<img src=\"{$row['doc']['artwork']}\" alt=\"my image \" width=\"250\" /><br /><br />"; 

     $songCount = 0; 
     foreach ($row['doc']['tracks'] as $song) { 
      ++$songCount; 
      echo $song['name'] . ' - '; 

      $songUrl = $row['doc']['baseurl'] . urldecode($song['url']); 
      echo "<a href=\"{$songUrl}\">{$songUrl}</a><br />"; 
     } 
     echo '<br /><br />'; 
    } 

    exit; 
?> 

JSON（http://www.godsgypsychristianchurch.net/music.json）：

{"total_rows":1,"offset":0,"rows":[ 

       {"id":"All Things Are Possible", 
"key":"All Things Are Possible", 
"doc":{"_id":"All Things Are Possible", 
"album":"All Things Are Possible", 
"artwork":"http://godsgypsychristianchurch.net/music_artwork/DEFAULT_COVER2.png", 
"baseurl":"http://www.godsgypsychristianchurch.net/music", 
"church":"Atlanta GA", 
"cityartwork":"http://www.ggcc.tv/LogoNE.png", 
"des":"All Things Are Possible from the Atlanta GA Church, Pastor Nick White", 
"tracks":[ 
    {"name":"1 Intro", 
     "url":"/Atlanta%20GA/All%20things%20are%20possible/01%20Intro.mp3"}, 

      {"name":"2 Wo si O Drom", 
     "url":"/Atlanta%20GA/All%20things%20are%20possible/02%20Wo%20si%20O%20drom.mp3"}, 

      {"name":"3 Nas Murrgo Shov", 
     "url":"/Atlanta%20GA/All%20things%20are%20possible/03%20Nas%20murrgo%20shov.mp3"}, 

      {"name":"4 To Cho Vos", 
     "url":"/Atlanta%20GA/All%20things%20are%20possible/04%20To%20cho%20vos.mp3"}, 

      {"name":"5 Tu Son Kai Sastridas", 
     "url":"/Atlanta%20GA/All%20things%20are%20possible/05%20Tu%20son%20kai%20sastridas.mp3"}, 

      {"name":"6 Now I Am Strong", 
     "url":"/Atlanta%20GA/All%20things%20are%20possible/06%20Now%20I%20am%20strong.mp3"}, 

      {"name":"7 Sorr Nevee", 
     "url":"/Atlanta%20GA/All%20things%20are%20possible/07%20Zorr%20nevee.mp3"}, 

      {"name":"8 Preaching", 
     "url":"/Atlanta%20GA/All%20things%20are%20possible/08%20Preaching.mp3"}, 

      {"name":"9 Arkadyan Amey", 
     "url":"/Atlanta%20GA/All%20things%20are%20possible/09%20Arkadyan%20amey.mp3"}, 

      {"name":"10 O Christo Ka Wudarr", 
     "url":"/Atlanta%20GA/All%20things%20are%20possible/10%20O%20Christo%20ka%20wudarr.mp3"}, 

      {"name":"11 Eloi, Eloi", 
     "url":"/Atlanta%20GA/All%20things%20are%20possible/11%20Eloi%2C%20Eloi.mp3"}, 

      {"name":"12 Amadow Dell", 
     "url":"/Atlanta%20GA/All%20things%20are%20possible/12%20Amadow%20Dell.mp3"}, 

      {"name":"13 Sastiar Amey Devla", 
     "url":"/Atlanta%20GA/All%20things%20are%20possible/13%20Sastiar%20amey%20Devla.mp3"}, 

      {"name":"14 Tu Skepeese", 
     "url":"/Atlanta%20GA/All%20things%20are%20possible/14%20Tu%20skepeese.mp3"}, 

      {"name":"15 Dov Ma Godgee", 
     "url":"/Atlanta%20GA/All%20things%20are%20possible/15%20Dov%20ma%20godgee.mp3"}, 

      {"name":"16 The Lord is my strength", 
     "url":"/Atlanta%20GA/All%20things%20are%20possible/16%20The%20Lors%20is%20my%20strength.mp3"} 
    ]}}, 

Answer 1

說你想教會鏈接到他們的音樂，首先將通過循環和教會的名字，擺陣，重複數據刪除它們，把它們打印出來，將它們鏈接像

$churches = array(); 

foreach ($json['rows'] as $row) 
{ 
    if (!in_array($row[doc]['church'], $churches)) 
     $churches[] = $row[doc]['church']; 
} 

foreach ($churches as $church) 
{ 
    print '<a href="getchurchmusic.php?churchname=' . urlencode($church) . '><br />' . htmlentities($church) . '</a>'; } 
} 

然後getchurchmusic.php你現在正在做的，但在教會過濾什麼

foreach ($json['rows'] as $row) 
    { 
      if ($_GET['churchname'] == $row[doc]['church']) 
      { 
        /* print out songs or whatever */ 

      } 
    } 

這不是測試，這不是有效的 - 你應該把所有這些數據在數據庫，緩存文件等，而不是XSS免費的，這只是粗略的代碼給你一個起點