我的Codeigniter視圖,我有以下代碼通過jquery ajax函數發送當前和新密碼給控制器,但它好像數據沒有傳遞給控制器。 看看你能否幫助我。Jquery ajax無法發佈數據
var url = '<?php echo base_url();?>index.php/it_inventory/change_my_pass';
$.ajax({
type: "POST",
url: url,
//datatype: "json",
data:'cu_pass=' + cu_pass + '&new_pass=' + new_pass,
success: function(r){
if(r==1){
alert("Password Changed Successfully!");
}else{
alert("Error changing password!");
}
}
});
控制器:
public function change_my_pass($cu_pass="", $new_pass=""){
//$cu_pass = $this->input->post('cu_pass');
//$new_pass = $this->input->post('new_pass');
echo $this->it_inventory_model->change_my_pass($cu_pass, $new_pass);
}
但你在哪裏甚至p在你的文章中分配數據? – 2013-03-06 06:04:50