環路因條件而終止，但條件是必要的？

Question

我正在研究一個猜謎遊戲。

問題是我必須將remainingguesses設置爲0，這樣一個人可以使得猜測的數量減少1個。但是同時循環中設置的條件是基於remainingguesses不是0。它是0循環終止並繼續。

我不知道如何解決這個問題，同時使循環中的條件正常工作。

這裏是有問題的循環：

printf("Type the number of guesses that player 2 gets and press return: \n"); 
    scanf("%d",&guesses); 

    remainingguesses = 0; 

    while (remainingguesses != 0) { 
    printf("Player 2: Type your guess and press return (guesses remaining:%d):\n",remainingguesses); 
    scanf(" %d",&secretnumberguess); 
    remainingguesses = guesses - 1; 

    if (secretnumberguess > secretnumber) { 
     printf("Your guess was greater than the secret number.\n"); 
    } 

    else if (secretnumberguess < secretnumber){ 
     printf("Your guess was less than the secret number.\n"); 
    } 

    else{ 
      printf("Your guess was equal to the secret number. You win!\n"); 
    } 
    } 

    if (remainingguesses == 0) 
    printf("Sorry you are out of guesses. You lose.\n"); 

如果需要，這裏是有問題的全碼：

#include <stdio.h> 

int main() 
{ 

    int secretnumber; 
    int guesses; 
    int secretnumberguess; 
    int remainingguesses; 

    while (1) { 
    printf("Player 1: Type a number between 0 and 99 and press return:\n"); 
    scanf(" %d",&secretnumber); 

    if (secretnumber > 99 || secretnumber < 0) { 
     printf("Secret number cannot be greater than 99 or below 0.\n"); 
     continue; 
    } 
    break; 
    } 

    printf("Type the number of guesses that player 2 gets and press return: \n"); 
    scanf("%d",&guesses); 

    remainingguesses = 0; 

    while (remainingguesses != 0) { 
    printf("Player 2: Type your guess and press return (guesses remaining:%d):\n",remainingguesses); 
    scanf(" %d",&secretnumberguess); 
    remainingguesses = guesses - 1; 

    if (secretnumberguess > secretnumber) { 
     printf("Your guess was greater than the secret number.\n"); 
    } 

    else if (secretnumberguess < secretnumber){ 
     printf("Your guess was less than the secret number.\n"); 
    } 

    else{ 
      printf("Your guess was equal to the secret number. You win!\n"); 
    } 
    } 

    if (remainingguesses == 0) 
    printf("Sorry you are out of guesses. You lose.\n"); 

    return 0; 

Answer 1

簡化代碼：

#include <stdio.h> 

int main() 
{ 

    int secretnumber; 
    int guesses; 
    int secretnumberguess; 
    int flag=0; 

    while (1) { 
    printf("Player 1: Type a number between 0 and 99 and press return:\n"); 
    scanf(" %d",&secretnumber); 

    if (secretnumber > 99 || secretnumber < 0) { 
     printf("Secret number cannot be greater than 99 or below 0.\n"); 
     continue; 
    } 
    break; 
    } 

    printf("Type the number of guesses that player 2 gets and press return: \n"); 
    scanf("%d",&guesses); 


    while (guesses > 0 && flag==0) { 
    printf("Player 2: Type your guess and press return (guesses remaining:%d):\n",guesses); 
    scanf(" %d",&secretnumberguess); 
    guesses=guesses - 1; 

    if (secretnumberguess > secretnumber) { 
     printf("Your guess was greater than the secret number.\n"); 
    } 

    else if (secretnumberguess < secretnumber){ 
     printf("Your guess was less than the secret number.\n"); 
    } 

    else{ 
      printf("Your guess was equal to the secret number. You win!\n"); 
      flag=1; 
    } 
    } 

    if (guesses == 0 && flag==0) 
    printf("Sorry you are out of guesses. You lose.\n"); 

    return 0; 
} 

Answer 2

這裏可能是這個編碼的簡單方式。

read guesses; 

while (guesses > 0) { 
    read input; 
    if (input == secret) { 
    print "you win!!"; 
    return; 
    } 
    else { 
    print "try again!"; 
    } 
    guesses--; 
} 

print "Sorry! You are out of guesses";