使用PHP返回整個頁面而不是分頁div的Ajax分頁

Question

我有一個php網站，它必須以分頁格式顯示頁面上的項目列表。我使用php實現了這一點，但現在我想爲它添加ajax功能。所以我添加了這個函數，通過點擊分頁部分中的頁面號來調用。 。 阿賈克斯/ jQuery函數:(分頁是網頁的鏈接的類）

$(document).ready(function() 
{ 
$('.paginate').live('click', function(e) 
{ 
    //alert("Here"); 
    e.preventDefault(); 
    var btnPage = $(this); 
    //alert(btnPage.attr('href'));  /RealEstate/process.php?page=3&ipp=2&venue=Array $('#temp').load($(this).attr("href")+' #temp'); 
    var getUrl = btnPage.attr('href'); 
    //var dataLocality = { 'locality[]' : []}; 
    //alert(getUrl); 
    $.ajax(
    { 
     url:btnPage.attr('href'), 
     success : function(resp) 
     { 
      // replace current results with new results. 
      $('#project_section').html(resp); 
     }, 
     error : function() 
     { 
      window.location.href = btnPage.attr('href'); 
     } 
    }); 
}); 
}); 

我PAGINATE功能有點像這樣：

function paginate() 
{ 
    if(!isset($this->default_ipp)) $this->default_ipp='2'; 
    if($_GET['ipp'] == 'All') 
    { 
     $this->num_pages = 1; 

    } 
    else 
    { 
     if(!is_numeric($this->items_per_page) OR $this->items_per_page <= 0) $this->items_per_page = $this->default_ipp; 
     $this->num_pages = ceil($this->items_total/$this->items_per_page); 
    } 
    $this->current_page = (isset($_GET['page'])) ? (int) $_GET['page'] : 1 ; // must be numeric > 0 
    $prev_page = $this->current_page-1; 
    $next_page = $this->current_page+1; 
    if($_GET) 
    { 
     $args = explode("&",$_SERVER['QUERY_STRING']); 
     foreach($args as $arg) 
     { 
      $keyval = explode("=",$arg); 
      if($keyval[0] != "page" And $keyval[0] != "ipp") $this->querystring .= "&" . $arg; 
     } 
    } 

    if($_POST) 
    { 
     foreach($_POST as $key=>$val) 
     { 
      if($key != "page" And $key != "ipp") $this->querystring .= "&$key=$val"; 
     } 
    } 
    if($this->num_pages > 4) 
    { 
     $this->return = ($this->current_page > 1 And $this->items_total >= 10) ? "<a class=\"paginate\" href=\"$_SERVER[PHP_SELF]?page=$prev_page&ipp=$this->items_per_page$this->querystring\">&laquo; Previous</a> ":"<span class=\"inactive\" href=\"#\">&laquo; Previous</span> "; 

     $this->start_range = $this->current_page - floor($this->mid_range/2); 
     $this->end_range = $this->current_page + floor($this->mid_range/2); 

     if($this->start_range <= 0) 
     { 
      $this->end_range += abs($this->start_range)+1; 
      $this->start_range = 1; 
     } 
     if($this->end_range > $this->num_pages) 
     { 
      $this->start_range -= $this->end_range-$this->num_pages; 
      $this->end_range = $this->num_pages; 
     } 
     $this->range = range($this->start_range,$this->end_range); 

     for($i=1;$i<=$this->num_pages;$i++) 
     { 
      if($this->range[0] > 2 And $i == $this->range[0]) $this->return .= " ... "; 
      // loop through all pages. if first, last, or in range, display 
      if($i==1 Or $i==$this->num_pages Or in_array($i,$this->range)) 
      { 
       $this->return .= ($i == $this->current_page And $_GET['page'] != 'All') ? "<a title=\"Go to page $i of $this->num_pages\" class=\"current\" href=\"#\">$i</a> ":"<a class=\"paginate\" title=\"Go to page $i of $this->num_pages\" href=\"$_SERVER[PHP_SELF]?page=$i&ipp=$this->items_per_page$this->querystring\">$i</a> "; 
      } 
      if($this->range[$this->mid_range-1] < $this->num_pages-1 And $i == $this->range[$this->mid_range-1]) $this->return .= " ... "; 
     } 
     $this->return .= (($this->current_page < $this->num_pages And $this->items_total >= 10) And ($_GET['page'] != 'All') And $this->current_page > 0) ? "<a class=\"paginate\" href=\"$_SERVER[PHP_SELF]?page=$next_page&ipp=$this->items_per_page$this->querystring\">Next &raquo;</a>\n":"<span class=\"inactive\" href=\"#\">&raquo; Next</span>\n"; 
     $this->return .= ($_GET['page'] == 'All') ? "<a class=\"current\" style=\"margin-left:10px\" href=\"#\">All</a> \n":"<a class=\"paginate\" style=\"margin-left:10px\" href=\"$_SERVER[PHP_SELF]?page=1&ipp=All$this->querystring\">All</a> \n"; 
    } 
    else 
    { 
     for($i=1;$i<=$this->num_pages;$i++) 
     { 
      $this->return .= ($i == $this->current_page) ? "<a class=\"current\" href=\"#\">$i</a> ":"<a class=\"paginate\" href=\"$_SERVER[PHP_SELF]?page=$i&ipp=$this->items_per_page$this->querystring\">$i</a> "; 
     } 
     $this->return .= "<a class=\"paginate\" href=\"$_SERVER[PHP_SELF]?page=1&ipp=All$this->querystring\">All</a> \n"; 
    } 
    $this->low = ($this->current_page <= 0) ? 0:($this->current_page-1) * $this->items_per_page; 
    if($this->current_page <= 0) $this->items_per_page = 0; 
    $this->limit = ($_GET['ipp'] == 'All') ? "":" LIMIT $this->low,$this->items_per_page"; 
} 

在網頁，我想顯示分頁div，我得到整個頁面作爲迴應，而不是分頁div。我已將分頁的div分隔到一個單獨的頁面，並將其包括在顯示頁面上（下面添加代碼），但無法正常工作。

<div id="project_section"> 
    <?php include_once("cityPropertySearchResults.php");?>   
</div> 

有人可以拋出一些光嗎？
更新： 我發現了類似here

此工程的聯繫，但現在，所有的js文件去加載一遍又一遍，遞歸的東西。

謝謝你的時間。

Answer 1

首先在第一頁加載之後將限制開始值設置爲0，將限制開始值作爲每頁限制並將該值通過ajax並在查詢中使用該限制開始（例如SELECT * FROM tbl LIMIT 0， 10;）